我不明白键盘功能[已关闭]

Question

\\Arduino\\KeyPad\\KeyPad.ino: In function 'void setup()':

\\Arduino\\KeyPad\\KeyPad.ino:24:9: error: expected unqualified-id before '.' token
Keypad.tick();
^

\\Arduino\\KeyPad\\KeyPad.ino: In function 'void loop()':

\\Arduino\\KeyPad\\KeyPad.ino:29:9: error: expected unqualified-id before '.' token
Keypad.begin();
^

\\Arduino\\KeyPad\\KeyPad.ino:34:16: error: expected primary-expression before '.' token
while (Keypad.available()) {
^

\\Arduino\\KeyPad\\KeyPad.ino:35:5: error: 'keypadEvent' was not declared in this scope
keypadEvent e = Keypad.read();
^\~\~\~\~\~\~\~\~\~\~

\\Arduino\\KeyPad\\KeyPad.ino:35:5: note: suggested alternative: 'KeypadEvent'
keypadEvent e = Keypad.read();
^\~\~\~\~\~\~\~\~\~\~
KeypadEvent

\\Arduino\\KeyPad\\KeyPad.ino:36:24: error: 'e' was not declared in this scope
Serial.print((char)e.bit.KEY);
^

\\Arduino\\KeyPad\\KeyPad.ino:37:24: error: 'KEY_JUST_PRESSED' was not declared in this scope
if (e.bit.EVENT == KEY_JUST_PRESSED) Serial.println(" pressed");
^\~\~\~\~\~\~\~\~\~\~\~\~\~\~\~

\\Arduino\\KeyPad\\KeyPad.ino:38:29: error: 'KEY_JUST_RELEASED' was not declared in this scope
else if (e.bit.EVENT == KEY_JUST_RELEASED) Serial.println(" released");
^\~\~\~\~\~\~\~\~\~\~\~\~\~\~\~\~

exit status 1

Compilation error: expected unqualified-id before '.' token

代码

#include <Keypad.h>


const byte ROWS = 4;  //four rows
const byte COLS = 4;  //four columns
//define the cymbols on the buttons of the keypads
char hexaKeys[ROWS][COLS] = {
  { '1', '2', '3', 'A' },
  { '4', '5', '6', 'B' },
  { '7', '8', '9', 'C' },
  { '*', '0', '#', 'D' }
};
byte colPins[ROWS] = { 41, 43, 45, 47 };  //connect to the row pinouts of the keypad
byte rowPins[COLS] = { 33, 35, 37, 39 };  //connect to the column pinouts of the keypad

//initialize an instance of class NewKeypad
Keypad keypad = Keypad(makeKeymap(hexaKeys), rowPins, colPins, ROWS, COLS);
const String password = "1234";  // change your password here
String input_password;

void setup() {
  Serial.begin(9600);
  Keypad.tick();
  input_password.reserve(32);  // maximum input characters is 33, change if needed
}

void loop() {
  
  Keypad.begin();

  // put your main code here, to run repeatedly:
  

  while (Keypad.available()) {
    keypadEvent e = Keypad.read();
    Serial.print((char)e.bit.KEY);
    if (e.bit.EVENT == KEY_JUST_PRESSED) Serial.println(" pressed");
    else if (e.bit.EVENT == KEY_JUST_RELEASED) Serial.println(" released");
  }

  delay(10);

  char key = keypad.getKey();

  if (key) {
    Serial.println(key);

    if (key == '*') {
      input_password = "";  // clear input password
    } else if (key == '#') {
      if (password == input_password) {
        Serial.println("password is correct");
        // DO YOUR WORK HERE

      } else {
        Serial.println("password is incorrect, try again");
      }

      input_password = "";  // clear input password
    } else {
      input_password += key;  // append new character to input password string
    }
  }
}

我查找错误消息并修复它，并得到相同的错误消息。

Answer 1

Keypad.tick();

应该是

keypad.tick();

（小写字母很重要！）

然后将其应用于键盘的每个对象实例（不是 Keypad 键盘，第一个是类/类型！）
基本上 Arduino IDE 抱怨的每一行都是这样的：

\Arduino\KeyPad\KeyPad.ino:29:9: 错误: 之前预期的不合格 ID '.'令牌Keypad.begin(); ^

您应该在“K/键盘”一词中输入小写的 k 而不是大写的 K。

Answer 2

您在代码中包含标准 Arduino 库时，错误地使用了 Adafruit Keypad 库的接口/功能。

导入 Adafruit Keypad 库并使用您拥有的代码，或者更改您的代码/基于这些示例的代码：
https://github.com/Chris--A/Keypad/tree/master/examples