当OneTouchExpandable设置为true时,如何以编程方式设置JSplitPane以隐藏右/底组件?

问题描述 投票:4回答:5

JSplitPane,你有setOneTouchExpandable方法,它提供了2个按钮,以快速完全隐藏或完整显示JSplitPane

我的问题是你怎么能以编程方式“点击”JSplitPane上的隐藏按钮?

我可能错误地解释了自己。我希望splitpane在开始时只显示2个组件中的一个(这就是我点击的意思)。

这有效:

import javax.swing.*;

class SplitPaneDefault {
    public static void main(String[] args) {
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                JSplitPane sp = new JSplitPane(
                    JSplitPane.HORIZONTAL_SPLIT,
                    new JTree(),
                    new JTree());
                sp.setOneTouchExpandable(true);
                sp.setDividerLocation(0.0);
                JOptionPane.showMessageDialog(null, sp);
            }
        });
    }
}

但用0.0取代1.0并不能隐藏正确的组件。这是我的问题!

java swing jsplitpane
5个回答
5
投票
import javax.swing.*;

class SplitPaneDefault {
    public static void main(String[] args) {
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                JSplitPane sp = new JSplitPane(
                    JSplitPane.HORIZONTAL_SPLIT,
                    new JTree(),
                    new JTree());
                sp.setOneTouchExpandable(true);
                sp.setDividerLocation(0.0);
                JOptionPane.showMessageDialog(null, sp);
            }
        });
    }
}

用1.0替换0.0,你就得到了我的问题

阅读精细手册并解决问题。

此方法会立即根据其当前大小更改拆分窗格的大小。如果未正确实现拆分窗格并且在屏幕上,此方法将无效...

import javax.swing.*;

class SplitPaneDefault {
    public static void main(String[] args) {
        SwingUtilities.invokeLater(new Runnable() {
            public void run() {
                JSplitPane sp = new JSplitPane(
                    JSplitPane.HORIZONTAL_SPLIT,
                    new JTree(),
                    new JTree());
                sp.setOneTouchExpandable(true);
                JFrame f = new JFrame("Split Pane To Right");
                f.add(sp);
                f.pack();
                // sp now has a non-zero size!
                sp.setDividerLocation(1.0);
                f.setLocationByPlatform(true);
                f.setDefaultCloseOperation(JFrame.DISPOSE_ON_CLOSE);
                f.setVisible(true);
            }
        });
    }
}

2
投票

你可以简单地使用这个:

public void setDividerLocation(double proportionalLocation)

splitPane.setDividerLocation(0.0d);

要么。

splitPane.setDividerLocation(1.0d);

取决于您是要隐藏左侧组件的第一个还是右侧组件。


2
投票

这是另一个解决方案,可能有点脏,但它的工作原理;)我希望代码说明一切。

public class ExtOneTouchJSplitPane extends JSplitPane {
    private static final long serialVersionUID = -2320161961382260438L;

    JButton jBLeftUp;
    JButton jBRightDown;

    public ExtOneTouchJSplitPane() {
        super();
        setOneTouchExpandable(true);
        extractDividerButtons();
    }

    public ExtOneTouchJSplitPane(int newOrientation) {
        super(newOrientation);
        setOneTouchExpandable(true);
        extractDividerButtons();
    }

    public ExtOneTouchJSplitPane(int newOrientation, boolean newContinuousLayout) {
        super(newOrientation, newContinuousLayout);
        setOneTouchExpandable(true);
        extractDividerButtons();
    }

    public ExtOneTouchJSplitPane(int newOrientation, boolean newContinuousLayout, Component newLeftComponent, Component newRightComponent) {
        super(newOrientation, newContinuousLayout, newLeftComponent, newRightComponent);
        setOneTouchExpandable(true);
        extractDividerButtons();
    }

    public ExtOneTouchJSplitPane(int newOrientation, Component newLeftComponent, Component newRightComponent) {
        super(newOrientation, newLeftComponent, newRightComponent);
        setOneTouchExpandable(true);
        extractDividerButtons();
    }

    private void extractDividerButtons() {
        BasicSplitPaneUI ui = (BasicSplitPaneUI) getUI();
        jBLeftUp = (JButton) ui.getDivider().getComponent(0);
        jBRightDown = (JButton) ui.getDivider().getComponent(1);
    }

    public void oneTouchClickLeft() {
        jBLeftUp.doClick();
    }

    public void oneTouchClickRight() {
        jBRightDown.doClick();
    }

    public void oneTouchClickUp() {
        jBLeftUp.doClick();
    }

    public void oneTouchClickDown() {
        jBRightDown.doClick();
    }
}

以及如何使用它的示例:

public class SplitPaneDemo extends JFrame implements Runnable {

    public static void main(String[] args) {
        SwingUtilities.invokeLater(new SplitPaneDemo());
    }

    ExtOneTouchJSplitPane hSplitPane;
    ExtOneTouchJSplitPane vSplitPane;

    public SplitPaneDemo() {
        createView();
    }

    public void createView() {
        setTitle("SplitPane-Demo");
        setLayout(new BorderLayout(0, 0));

        hSplitPane = new ExtOneTouchJSplitPane();
        JButton jBLeft = new JButton("<html><body> &nbsp;<br>Left Component<br> &nbsp;</body></html>");
        JButton jBRight = new JButton("<html><body> &nbsp;<br>Right Component<br> &nbsp;</body></html>");
        jBLeft.addActionListener(new ActionListener() {
            @Override
            public void actionPerformed(ActionEvent e) {
                hSplitPane.oneTouchClickLeft();
            }
        });
        jBRight.addActionListener(new ActionListener() {
            @Override
            public void actionPerformed(ActionEvent e) {
                hSplitPane.oneTouchClickRight();
            }
        });
        hSplitPane.setLeftComponent(jBLeft);
        hSplitPane.setRightComponent(jBRight);

        add(hSplitPane, BorderLayout.CENTER);

        vSplitPane = new ExtOneTouchJSplitPane(JSplitPane.VERTICAL_SPLIT);
        JButton jBUp = new JButton("<html><body> &nbsp;<br>Up Component<br> &nbsp;</body></html>");
        JButton jBDown = new JButton("<html><body> &nbsp;<br>Down Component<br> &nbsp;</body></html>");
        jBUp.addActionListener(new ActionListener() {
            @Override
            public void actionPerformed(ActionEvent e) {
                vSplitPane.oneTouchClickUp();
            }
        });
        jBDown.addActionListener(new ActionListener() {
            @Override
            public void actionPerformed(ActionEvent e) {
                vSplitPane.oneTouchClickDown();
            }
        });
        vSplitPane.setTopComponent(jBUp);
        vSplitPane.setBottomComponent(jBDown);

        add(vSplitPane, BorderLayout.SOUTH);
    }

    @Override
    public void run() {
        setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
        setSize(400, 400);
        setVisible(true);

        hSplitPane.oneTouchClickLeft();
    }
}

1
投票

解决setDividerLocation(1.0)在框架变得可显示之前无法工作的问题,可以使用AncestorListener

sp.addAncestorListener(new AncestorListener {
  def ancestorAdded  (event: AncestorEvent): Unit = sp.setDividerLocation(1.0)

  def ancestorRemoved(event: AncestorEvent): Unit = ()
  def ancestorMoved  (event: AncestorEvent): Unit = ()
})

1
投票

@0__'s answer暗示您应该使用AncestorListener来设置分频器位置,并将其考虑在内(ComponentListener是不够的,我不知道为什么)。

但是,这还不够:如果分割平面以某种方式调整大小(例如,因为它的布局管理器决定它应该,当框架已经调整大小时),您想要隐藏的组件的一小部分仍将显示。这是由于组件最小尺寸不为零。它可以通过使用setMinimumSize(new Dimension())对其进行归零来解决(如that other answer中所述),但如果这不是一个选项,则可以入侵分割窗格UI:

如果你使用标准的BasicSplitPaneUI,你可以破解它的keepHidden布尔字段并强制它到true,所以分隔符将坚持到任何一方:

sp.addAncestorListener(new AncestorListener() {
    @Override
    public void ancestorAdded(AncestorEvent event) {
        sp.setDividerLocation(1.0); // Divider is positioned
        Field m = BasicSplitPaneUI.class.getDeclaredField("keepHidden");
        m.setAccessible(true);
        m.set(sp.getUI(), true); // Divider position will stick
        //sp.removeAncestorListener(this); // Uncomment for a one-shot event
    }

    @Override public void ancestorRemoved(AncestorEvent event) { }
    @Override public void ancestorMoved(AncestorEvent event) { }
});
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