如何使用PowerShell从XML文件中获取exitcode?

问题描述 投票:-2回答:1

我有一个XML文件,如下所示:

<Feature>
    <B7>A</B7>
    <B8>B</B8>
    <B9>C</B9>
    <ExitCode>
        <Found>123</Found>
        <NotFound>789</NotFound>
    </ExitCode>
</Feature>

我有一个PowerShell脚本看起来像这样:

$regex = [regex]$Pattern
$matching = $regex.Match($FB)
if ($matching.Success) {
    while ($matching.Success) {
        "Match found: {0}" -f $matching.Value
        exit 123 #I want to delete this
        $matching = $matching.NextMatch()
    }
} else {
    "Not Found" 
    exit 789 #I want to delete this
}

我想得到exitcode,但我不想写exit 123exit 780,我只是想从XML文件调用退出代码,所以每次我想改变exitcode号,我只是从XML文件修改,而不是从PowerShell脚本。

所以,如果我使用批处理文件运行脚本,我可以获取exitcode日志,如下所示:

set log=C:\Users\Log.txt
set PS=C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe
set PS=%PS%\powershell.exe -ExecutionPolicy Bypass -File 

"C:\Windows\System32\WindowsPowerShell\v1.0\powershell.exe" -ExecutionPolicy Bypass -File C:\Users\XML.ps1 -i C:\Users\Feature.txt -j C:\Users\XML.xml

echo %ERRORLEVEL% > "%log%"
xml powershell batch-file exit-code
1个回答
1
投票

像这样的东西;读取XML文件,然后通过属性引用从中获取数字:

$xmlData = New-Object -TypeName System.Xml.XmlDocument
$xmlData.Load('c:\test\data.xml')

$regex = [regex]$Pattern
$matching = $regex.Match($FB)
if ($matching.Success) {
    while ($matching.Success) {
        "Match found: {0}" -f $matching.Value
        exit $xmlData.Feature.ExitCode.Found
        $matching = $matching.NextMatch()
    }
} else {
    "Not Found" 
    exit $xmlData.Feature.ExitCode.NotFound
}

编辑:更新以获得更好的XML处理,可以正确处理XML文件编码。感谢@ tomalak的评论。

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