我想知道如何在Cypher中获取列表的子集?
让我们假设以下Cypher查询:
WITH ['a','b','c'] AS set1, ['b'] AS set2
RETURN set1, set2
我想得到RETURN
的set3
结果,set1
是['a','c']
的一个子集,仅包含值set2
。因此过滤掉了['b']
(此样本中的WITH ['a','b','c'] AS set1, ['b'] AS set2
RETURN [item in set1 WHERE NOT item in set2] as set3
值)的内容。
任何想法如何做到这一点?
谢谢,Koen
使用Cypher,您可以在列表中使用过滤器操作,确保您保留的唯一值不是第二个列表中的值:
APOC Procedures plugin
虽然如果你有WITH ['a','b','c'] AS set1, ['b'] AS set2
RETURN apoc.coll.subtract(set1, set2) as set3
,你可以使用其中一个集合函数来执行列表减法:
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