简化可迭代逻辑

Question

我有这个代码有效。它循环遍历一个对象列表，并获取对象的一个​​属性存在于另一个对象列表中的所有对象。

    List<WatchedGame> watching = List<WatchedGame>();
    for (WatchedGame watchedGame in watchedGames.list) {
      if (week.games.contains(watchedGame))
        watching.add(watchedGame);
    }

好像我可以简化这个代码。

    List<WatchedGame> watching = watchedGames.list.where((watchedGame) {
      week.games.contains(watchedGame.game);
    });

但是我得到了这个例外。

type 'WhereIterable<WatchedGame>' is not a subtype of type 'List<WatchedGame>'

Answer 1

在最后投掷toList电话：

List<T> newList = list.where(condition).toList();