我有以下代码:
set MARKER_LIST = "t14_noTap_leftSlow t24_noTap_leftMedium t34_noTap_leftFast \
t44_noTap_rightSlow t54_noTap_rightMedium t64_noTap_rightFast \
t74_noTap_inphaseSlow t84_noTap_inphaseMedium t94_noTap_inphaseFast \
t104_noTap_antiphaseSlow t114_noTap_antiphaseMedium t124_noTap_antiphaseFast"
foreach code (${MARKER_LIST})
set evt_code = `echo ${code} | sed 's/^.*t[0-9]*_noTap_//'`
echo "Extracted value: $evt_code"
end
我试图提取“tXX_noTap_”和“tXXX_noTap_”之后的字符串,但它似乎不起作用。对此有任何帮助将不胜感激。谢谢!
我猜你已经快到了
在 sed 语句末尾使用“
g
”选项来替换所有出现的情况。
如果您想替换以 ^.*
开头的每个出现,您不想在正则表达式中添加
tXX_noTap_
前缀
echo "t14_noTap_leftSlow t24_noTap_leftMedium t34_noTap_leftFast \
t44_noTap_rightSlow t54_noTap_rightMedium t64_noTap_rightFast \
t74_noTap_inphaseSlow t84_noTap_inphaseMedium t94_noTap_inphaseFast \
t104_noTap_antiphaseSlow t114_noTap_antiphaseMedium t124_noTap_antiphaseFast" | sed 's/t[0-9]*_noTap_//g'