涉及COUNT（）和LOWER（）的Spring JPA查询

Question

我对Spring JPA / JPQL还是很陌生，但是尝试复制以下MySQL查询，但没有成功。我们无法克服看起来像语法错误的问题，它似乎是试图将COUNT（）和LOWER（）的使用组合起来的功能。

MySQL（有效）是：

select lower(sdetail_cvalue) as stringValue, 
count(lower(sdetail_cvalue)) as stringValueCount 
from <someTable>
where sdetail_cfield not like <someValue>
and sdetail_cfield not like <someOtherValue>
and sdetail_cfield not like <someOtherOtherValue>
group by stringValue
order by stringValueCount desc

和我正在尝试的相应JPQL是

SELECT new <searchResult> 
(lower(sd.searchText) as searchText, 
COUNT(lower(sd.searchText)) as searchTextOccurrenceCount) 
FROM <someTable> sd 
WHERE sd.searchType not like <someValue> 
AND sd.searchType not like <someOtherValue> 
AND sd.searchType not like <someOtherOtherValue> 
GROUP BY searchText 
ORDER BY searchTextOccurrenceCount DESC

但是在执行时收到以下错误消息

Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: expecting CLOSE, found '(' near line 1, column 128 [SELECT new <REDACTED> (lower(sd.searchText) as searchText, COUNT(lower(sd.searchText)) as searchTextOccurrenceCount) FROM <someTable> sd WHERE sd.searchType not like <someValue> AND sd.searchType not like <someOtherValue> AND sd.searchType not like <someOtherOtherValue> GROUP BY searchText ORDER BY searchTextOccurrenceCount DESC]

我已经编辑了上面的部分内容，但是列号（即128）是指“（”在“ lower”和“ sd”之间。

我们已经尝试了各种方法来解构查询以查明问题，这似乎是我们使用了复合COUNT（LOWER（））构造。有没有人有使用JPQL成功实现这样的事情的示例？...预先感谢。

Answer 1

您是否考虑过将nativeQuery = true添加到@Query注释中？