我不断收到以下错误,我不知道为什么指数成为功能型,当我运行的代码,并返回整数。
异常发生:“INT”和“功能”:用于/ exceptions.TypeError不受支持的操作数类型
这里是我的代码:
def Zero(*eq):
if len(eq) == 0:
index = 0
return index
else:
index = eq[0][0]
k = eq[0][1]
if k == "+":
res = index + 0
elif k == "-":
res = index - 0
elif k == "x":
res = index * 0
elif k == "/":
res = 0 / index
else:
if index != 0:
res = 0 // index
if index == 0:
error = "Division with zero is invalid"
return error
else:
return res
def Eight(*eq):
if len(eq) == 0:
index = 8
return index
else:
index = eq[0][0]
k = eq[0][1]
if k == "+":
res = index + 8
elif k == "-":
res = index - 8
elif k == "x":
res = index * 8
elif k == "/" and index != 0:
res = 8 / index
else:
if index != 0:
res = 8 // index
if index == 0:
error = "Division with zero is invalid"
return error
else:
return res
def Divide(num):
k = '/'
return (num, k)
这是我执行代码:
x = Zero(Divide(Eight))
print(x)
你应该把括号函数对象后调用的函数Eight
;否则函数对象本身作为参数传递到Divide
:
x = Zero(Divide(Eight()))