我需要生成以下格式的XML:
我没有在任务的 xml 部分走得太远,因为我遇到了以下情况,你可以看出这显然不是我的意图。
考虑到 BBAN 和 IBAN 需要位于
以及我希望其根据第一张图片进行格式化,我该如何正确处理这个问题。AccountNo
完整的查询以及我生成 xml 的公平尝试如下所示:
DECLARE @AccountType NVARCHAR(3);
DECLARE @kodBanke NVARCHAR(3);
SET @AccountType = 'T';
SET @kodBanke = ( SELECT vrednost FROM dbini WHERE IDENT = 'KOD' AND SECTION = 'PP' );
WITH Ent_Posta
AS
(
SELECT e.naziv,p.posta,e.sifra
FROM entitet AS e
INNER JOIN poste AS p ON e.sifra = p.entitet
)
SELECT (
SELECT
[dbo].[brojracuna](@kodBanke,i.partija) AS 'BBAN',
[dbo].[GENERATEIBAN](i.partija) AS 'IBAN'
FOR XML PATH('AccountNo'), ELEMENTS, ROOT('Account')
),
@accountType AS 'AccountType',
(a.ime + ' ( ' + a.roditel + ' ) ' + a.prezime) AS 'Name',
a.embg AS 'UID',
CASE status
WHEN 2 THEN 'A'
WHEN 4 THEN 'B'
WHEN 8 THEN 'U'
END AS 'Status',
c.sifra AS 'Territory',
@kodBanke as 'ID_Bank',
REPLACE(CONVERT(VARCHAR(10), i.DOTVaRANJE, 120), '.', '') + '-' + RIGHT( '0' + CONVERT(VARCHAR(2), DATEPART(hh, i.DOTVaRANJE)), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(mi, i.DOTVaRANJE)), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(s, i.DOTVaRANJE)),2) AS OpeningDate,
REPLACE(CONVERT(VARCHAR(10),'2006.09.28 ', 120), '.', '') + '-' + RIGHT( '0' + CONVERT(VARCHAR(2), DATEPART(hh, '2006.09.28' )), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(mi, '2006.09.28 ')), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2),DATEPART(s,'2006.09.28 ')),2) AS ClosingDate
FROM adresar AS a
INNER JOIN istdden AS i
ON a.embg = i.embg
INNER JOIN Ent_Posta as c
ON a.postbroj = c.posta
FOR XML PATH ('Account'), ROOT('Accounts');
删除这部分后,我得到...
<Accounts>
<Account>
<BBAN>5710543102313248</BBAN>
<IBAN>BA39531231634039248</IBAN>
<AccountType>T</AccountType>
<Name>DARKO ( DRAGAN ) TESIC</Name>
<UID>0000005467234</UID>
<Status>A</Status>
<Territory>1</Territory>
<ID_Bank>571</ID_Bank>
<OpeningDate>20081205-000000</OpeningDate>
<ClosingDate>20060928-000000</ClosingDate>
</Account>
...但现在
AccountNO
不见了。
如果我理解正确的话 - 你正在与
1:1
值作斗争,但在一些更深的嵌套中。
您可以在
XPath
中使用与 []
相关的类似 FOR XML PATH
的表达式。看看这个:
SELECT 'blah' AS FirstNode
,'blub' AS [SecondNode/OneDeeper]
,'blib' AS [SecondNode/OneMore]
,'ballaballa' AS [ThirdNode]
FOR XML PATH('row'),ROOT('root');
结果(特别看
<SecondNode>
:
<root>
<row>
<FirstNode>blah</FirstNode>
<SecondNode>
<OneDeeper>blub</OneDeeper>
<OneMore>blib</OneMore>
</SecondNode>
<ThirdNode>ballaballa</ThirdNode>
</row>
</root>
对于您的问题,在查询中使用
AS [AccountNo/IBAN]
可能就足够了。