mysql右边连接多个表

Question

我是mySQL的新手，我正在努力编写一个查询，列出所有已扫描产品价格的商店以及尚未扫描的商店。以下为单个产品提供了正确的结果：

select distinct(s.id) as store_id, s.chainID as chain_id, p1.productID as product_id, 
s.chain, s.location, s.city, prd.brand, prd.product, prd.quantity, prd.size, prd.unit
from analytics.price p1        -- Fact table with prices
join analytics.pricetime pt   -- Dimension table with time a price was scanned
on p1.priceTimeID = pt.id
join analytics.product prd    -- Dimension table with products
on p1.productID = prd.id
and prd.published = 1
right join analytics.store s   -- Dimension table with stores and the chain they belong to
on p1.storeID = s.id
and p1.chainID = s.chainID
and p1.productID = 46720
and p1.priceTimeID between 2252 and 2265
where s.published=1
and s.chainID = 5;

当我删除p1.productID = 46720条款以获得所有产品的结果时，我得到所有已扫描价格的商店（正确），但右边加入的无价格一侧仅显示未扫描任何价格的商店任何产品。 （这是一个简单的星型模式，具有价格事实和产品，时间和商店的尺寸）。我非常感谢帮助 - 我已经尝试过各种方式，包括“in”，“not exists”和光标存储过程，但我似乎每次尝试都会碰壁砖。

编辑澄清：

这是我想要实现的目标：

Price table
Product Chain       Store       Price
100     5       1       $10
101     5       2       $20

Store table
Chain   Store
5       1
5       2
5       3

Desired Result
Product Chain   Store       Price
100     5       1       $10
100     5       2       NULL
100     5       3       NULL
101     5       1       NULL
101     5       2       $20
101     5       3       NULL


Actual Result
Product Chain   Store       Price
100     5       1       $10
101     5       2       $20
NULL    5       3       NULL

Answer 1

我更喜欢使用LEFT JOIN的可读性 - 这应该返回chainid 5中所有已发布的商店和相关产品（给定标准）。

select distinct s.id as store_id, s.chainID as chain_id, s.chain, s.location, s.city, 
    prd.id as product_id, prd.brand, prd.product, prd.quantity, prd.size, prd.unit
from analytics.store s   
    left join analytics.price p1        
        on p1.storeID = s.id
            and p1.chainID = s.chainID
            and p1.priceTimeID between 2252 and 2265
    left join analytics.product prd    
        on p1.productID = prd.id
            and prd.published = 1
    left join analytics.pricetime pt   
        on p1.priceTimeID = pt.id
where s.published=1
    and s.chainID=5;

编辑 - 发表评论，看起来你正在寻找笛卡尔积：

SELECT P.Product, P.Chain, S.Store, IF(P.Store=S.Store,P.Price,NULL) Price
FROM Price P, Store S
WHERE P.Chain = 5
  AND S.Chain = P.Chain
ORDER BY P.Product, S.Store

SQL Fiddle Demo