再次选择选择Y时char不会重复执行while函数，但N仍会退出它

Question

我一直遇到do while循环不重复的问题。当提示再次添加两个数字时我选择N时，它将按预期退出程序，但是选择Y或y会使程序挂起，将我带到下一行，但使我无法键入任何内容。如果您能帮助我，我将不胜感激。谢谢！

#include <iostream>
using namespace std;
int main()
{

int number1, number2; //Two numbers
int sum;              //Sum
char again;     //For yet another attempt


{  //Inputting the two numbers

    cout << "\nEnter two numbers, and i will add them: ";
    cin >> number1 >> number2;

    //Adding the two numbers

    sum = number1 + number2;
    cout << "The sum of the two numbers you have picked is " << sum << "\n\n";

    //Does the user want to add two other numbers?
    cout << "Do you want to add two other numbers? (Y/N) ";
    cin >> again;
}
    while (again == ('y') || again == ('Y'));


   return 0;
}

Answer 1

do { statement} while(condition)

在循环语法在上面时执行，我想您在语法中错过了做世界的事情。