如何在1个web.xml中定义2个servlet

问题描述 投票:4回答:1

我尝试过thisthisthis。这些示例使用不同的框架。我正在使用Atmosphere + Jersey。我想在单个web.xml中了解如何配置2个servlet编辑:web.xml

<servlet>
    <description>AtmosphereServlet</description>
    <servlet-name>AtmosphereServlet</servlet-name>
    <servlet-class>org.atmosphere.cpr.AtmosphereServlet</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.example.package1</param-value>
    </init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>AtmosphereServlet</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>
<servlet>
    <description>Admin</description>
    <servlet-name>Admin</servlet-name>
    <servlet-class>org.atmosphere.cpr.AtmosphereServlet</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.example.package2</param-value>
    </init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Admin</servlet-name>
    <url-pattern>/admin/*</url-pattern>
</servlet-mapping>
java xml tomcat servlets jersey
1个回答
0
投票

我正在执行Java编码,但我从未发现在单个web.xml文件中执行10个servlet的问题。并有共同点请参见下面的示例代码

<servlet>
    <servlet-name>jsrUploadFile</servlet-name>
    <servlet-class>in.msedcl.se.jsrupload.JsrFileUpload</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>jsrUploadFile</servlet-name>
    <url-pattern>/jsrUploadFile</url-pattern>
</servlet-mapping>


<servlet>
    <servlet-name>installationUploadFiles</servlet-name>
    <servlet-class>in.msedcl.se.installationFilesUpload.InstallationFilesUpload</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>installationUploadFiles</servlet-name>
    <url-pattern>/installationUploadFiles</url-pattern>
</servlet-mapping>
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