我正在创建一个.txt文件，该团队中有四名士兵，按照功绩排名。士兵不给自己定级。
我有以下代码：
import itertools
# create a list of 4 soldiers
numSoldiers=4
soldiers = []
for i in range(1,numSoldiers+1):
soldiers.append('soldier'+str(i))
# create list of all permutations of 2 soldiers
perms = list(itertools.permutations(soldiers, 2))
# list of possible rankings (soldier does not rank himself/herself)
possRanks = list(range(1,len(soldiers)))
# create the edgelist .txt file with randomized rankings
open('peerRankingsEdgelist.txt', 'w').close() #delete contents of .txt file at the start
file = open('peerRankingsEdgelist.txt', 'w')
for i in perms:
file.write(i[0] + ', ' + i[1] + '\n')
file.close() #close file
将在.txt文件中产生以下输出：
soldier1, soldier2
soldier1, soldier3
soldier1, soldier4
soldier2, soldier1
soldier2, soldier3
soldier2, soldier4
soldier3, soldier1
soldier3, soldier2
soldier3, soldier4
soldier4, soldier1
soldier4, soldier2
soldier4, soldier3
对于三行的每组（以相同的soldier开头的行的集合），我想添加一个来自possRanks的随机排名，其中possRanks = [1, 2, 3]。问题是我不能完全随机化它，因为这样排名可能会重复。例如，soldier1可能将soldier2和soldier3的排名都定为1，这是我无法获得的。
正确的示例输出如下：
soldier1, soldier2, 3
soldier1, soldier3, 1
soldier1, soldier4, 2
soldier2, soldier1, 1
soldier2, soldier3, 2
soldier2, soldier4, 3
soldier3, soldier1, 2
soldier3, soldier2, 1
soldier3, soldier4, 3
soldier4, soldier1, 1
soldier4, soldier2, 2
soldier4, soldier3, 3
[此处，soldier1将soldier2的值为3，将soldier3的值为1，将soldier4的值为2。
以您的文件为例data.txt：
soldier1, soldier2
soldier1, soldier3
soldier1, soldier4
soldier2, soldier1
soldier2, soldier3
soldier2, soldier4
soldier3, soldier1
soldier3, soldier2
soldier3, soldier4
soldier4, soldier1
soldier4, soldier2
soldier4, soldier3
[我们可以使用itertools grouper recipe读取N个大小的文件，用possRanks随机排列random.shuffle，然后按random.shuffle每个组，每个随机排列的等级。然后，我们可以打开一个要写入的新文件，例如zip。
zip每次您执行上述操作时，都会在output.txt中随机写入等级排名：
from random import shuffle
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)
possRanks = [1, 2, 3]
with open("data.txt") as f, open("output.txt", mode="w") as o:
for line in grouper(map(str.strip, f), len(possRanks), ''):
shuffle(possRanks)
for group, rank in zip(line, possRanks):
o.write(f"{group}, {rank}\n")
这里是仅使用output.txt的另一种方法，它可能更易于解析；
soldier1, soldier2, 2
soldier1, soldier3, 1
soldier1, soldier4, 3
soldier2, soldier1, 1
soldier2, soldier3, 3
soldier2, soldier4, 2
soldier3, soldier1, 2
soldier3, soldier2, 3
soldier3, soldier4, 1
soldier4, soldier1, 3
soldier4, soldier2, 1
soldier4, soldier3, 2
所以我唯一更改的部分在这里：
enum基本上，我正在使用import itertools
import random
# create a list of 4 soldiers
numSoldiers=4
soldiers = []
for i in range(1,numSoldiers+1):
soldiers.append('soldier'+str(i))
# create list of all permutations of 2 soldiers
perms = list(itertools.permutations(soldiers, 2))
# list of possible rankings (soldier does not rank himself/herself)
possRanks = list(range(1,len(soldiers)))
# create the edgelist .txt file with randomized rankings
open('peerRankingsEdgelist.txt', 'w').close() #delete contents of .txt file at the start
file = open('peerRankingsEdgelist.txt', 'w')
for num, i in enumerate(perms):
if num % len(possRanks) == 0:
shuffled_ranks = possRanks.copy()
random.shuffle(shuffled_ranks)
random_rank = str(shuffled_ranks.pop())
line = (i[0]) + ', ' + i[1] + ',' + random_rank + '\n'
file.write(line)
file.close() #close file
来计算每次迭代，并且只创建每for num, i in enumerate(perms):
if num % len(possRanks) == 0:
shuffled_ranks = possRanks.copy()
random.shuffle(shuffled_ranks)
random_rank = str(shuffled_ranks.pop())
line = (i[0]) + ', ' + i[1] + ',' + random_rank + '\n'
次迭代的数量enumerate的新随机列表，其中possRanks等于x。然后，我们只从列表中弹出每个项目，基本上每x次迭代就用尽该列表，并在用尽后创建一个新列表。