SQL存储函数问题，返回错误

Question

CREATE FUNCTION salarystatus(employee_id integer) RETURNS VARCHAR(25)
DETERMINISTIC
BEGIN

   DECLARE isalary DECIMAL(8,2);
   DECLARE istatus varchar(25);

        SELECT salary INTO isalary 
        FROM employees
        WHERE employee_id = salarystatus.employee_id;

    IF (isalary < 50000) then
        SET istatus = 'low income';
    ELSEIF (50000 <= isalary < 80000) then
        SET istatus = 'medium income';
    ELSE 
        SET istatus = 'high income';
    ENDIF

    RETURN istatus

END

返回此错误：

1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'RETURN istatus

在第20行结束

这个查询看起来正确，这里的语法错误是什么？

Answer 1

问题是我写了ENDIF而不是“END IF”

最后添加这个。

$$ DELIMITER;

Answer 2

如果不是endif结束并且每个语句都需要终止

P.Salmon已经评论了，而我正在做出答案。

DELIMITER $$

CREATE FUNCTION
 # best to prefix with in_ so MySQL and you cant mix it up with existing columns
 salarystatus (in_employee_id INTEGER)
RETURNS VARCHAR(25)
BEGIN
  DECLARE isalary DECIMAL(8,2) DEFAULT NULL; # <- best to have a default value
  DECLARE istatus varchar(25)  DEFAULT NULL; # <- best to have a default value

  SELECT salary
  INTO isalary 
  FROM employees
  WHERE employee_id = in_employee_id.employee_id; #<- use the function in param

  IF (isalary < 50000) then
    SET istatus = 'low income';
  ELSEIF (50000 <= isalary < 80000) then
    SET istatus = 'medium income';
  ELSE 
    SET istatus = 'high income';
  END IF; # <- semicon (;) missing in your query also ENDIF isnt valid syntax. 

  RETURN istatus;
END

DELIMITER ;

我也删除DETERMINISTIC因为它不是真的需要。