默认API过滤器引用相关实体的嵌套属性时失败

问题描述 投票:0回答:1

我正在Symfony 4应用程序中从Api平台堆栈配置一系列ApiFilter类。我发现使用实体关系中的嵌套属性的任何过滤器都不起作用。请参阅下面的示例代码,非常感谢为什么它可能无法正常工作的任何帮助。

我想要过滤的实体是:

<?php

namespace App\Entity;

use ApiPlatform\Core\Annotation\ApiResource;
use Doctrine\ORM\Mapping as ORM;
use ApiPlatform\Core\Annotation\ApiProperty;

/**
 * PostAuthor
 * @ApiResource()
 * @ORM\Table(name="POST_AUTHOR", indexes={@ORM\Index(name="IDX_CF3397D94A7000A0", columns={"IDENTITY_ID"})})
 * @ORM\Entity(repositoryClass="App\Repository\PostAuthorRepository")
 */
class PostAuthor
{
    /**
     * @var string
     *
     * @ORM\Column(name="USER_ID", type="string", length=255, nullable=false)
     * @ORM\Id
     */
    private $userId;

    /**
     * @var string
     *
     * @ORM\Column(name="USERNAME", type="string", length=255, nullable=false)
     */
    private $username;

我过滤的集合是:

<?php

namespace App\Entity;

use Doctrine\Common\Collections\ArrayCollection;
use ApiPlatform\Core\Annotation\ApiResource;
use ApiPlatform\Core\Annotation\ApiFilter;
use Symfony\Component\Serializer\Annotation\Groups;
use ApiPlatform\Core\Bridge\Doctrine\Orm\Filter\SearchFilter;
use ApiPlatform\Core\Bridge\Doctrine\Orm\Filter\NumericFilter;
use Doctrine\ORM\Mapping as ORM;

/**
 * PostHeader
 * @ORM\Table(name="POST_HEADER", indexes={@ORM\Index(name="IDX_1CEEE7D0B65E5FF8", columns={"EMOTION_REF_ID"}), @ORM\Index(name="IDX_1CEEE7D08AFAAB14", columns={"AUTHOR_ID"})})
 * @ORM\Entity(repositoryClass="App\Repository\PostHeaderRepository")
 * @ApiResource(
 *       normalizationContext={"groups"={"postheader:read"}},
 *       denormalizationContext={"groups"={"postheader:write"}},
 *    )
 * @ApiFilter(SearchFilter::class, properties={"author.userId": "partial", "author.username": "partial"})
 */
class PostHeader
{

 /**
     * @var PostAuthor
     *
     * @ORM\ManyToOne(targetEntity="PostAuthor")
     * @ORM\JoinColumns({@ORM\JoinColumn(name="AUTHOR_ID", referencedColumnName="USER_ID")})
     * @Groups({"postheader:read"})
     */
    private $author;
symfony doctrine-orm api-platform.com
1个回答
0
投票

我只是测试一个与你相同的类的新项目,它的工作原理。我可以通过author.userId进行过滤。请告诉我们您的测试请求。和错误消息;)。

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