如何修复无法在{server ip}打开与Cassandra的本机连接:9042

问题描述 投票:0回答:1

我正在尝试使用spark-cassandra-connector连接spark和Cassandra。连接已建立,但当我尝试在JavaRDD上执行操作时,我正面临着。

   java.io.IOException: Failed to open native connection to Cassandra at {10.0.21.92}:9042

这是我试图实现的配置和代码:

    SparkConf sparkConf = new SparkConf().setAppName("Data Transformation").set("spark.serializer","org.apache.spark.serializer.KryoSerializer").setMaster("local[4]");
    sparkConf.set("spark.cassandra.connection.host", server ip);
    sparkConf.set("spark.cassandra.connection.port", "9042");
    sparkConf.set("spark.cassandra.connection.timeout_ms", "5000");
    sparkConf.set("spark.cassandra.read.timeout_ms", "200000");
    sparkConf.set("spark.cassandra.auth.username", user_name);
    sparkConf.set("spark.cassandra.auth.password", password);

    JavaSparkContext sparkContext = new JavaSparkContext(sparkConf);

以下是我在javardd上执行操作的代码:

    CassandraJavaRDD<CassandraRow> cassandraRDD = CassandraJavaUtil.javaFunctions(sparkContext).cassandraTable(keySpaceName, tableName);
    JavaRDD<GenericTriggerEntity> rdd = cassandraRDD.map(new Function<CassandraRow, GenericTriggerEntity>() {

    private static final long serialVersionUID = -165799649937652815L; 

    @Override
    public GenericTriggerEntity call(CassandraRow row) throws Exception {
    GenericTriggerEntity genericTriggerEntity = new GenericTriggerEntity();
    if(row.getString("end") != null)                        genericTriggerEntity.setEnd(row.getString("end"));
    if(row.getString("key") != null)
    genericTriggerEntity.setKey(row.getString("key"));
    genericTriggerEntity.setKeyspacename(row.getString("keyspacename"));
    genericTriggerEntity.setPartitiondeleted(row.getString("partitiondeleted"));
    genericTriggerEntity.setRowdeleted(row.getString("rowDeleted"));
    genericTriggerEntity.setRows(row.getString("rows"));
    genericTriggerEntity.setStart(row.getString("start"));
    genericTriggerEntity.setTablename("tablename");
    genericTriggerEntity.setTriggerdate(row.getString("triggerdate"));
    genericTriggerEntity.setTriggertime(row.getString("triggertime"));
    genericTriggerEntity.setUuid(row.getUUID("uuid"));
    return genericTriggerEntity;
    }               

    });

这是我正在执行的JavaRDD操作


    JavaRDD<String> jsonDataRDDwords = rdd.flatMap(s -> Arrays.asList(SPACE.split((CharSequence) s)));
    JavaPairRDD<String, Integer> jsonDataRDDones = jsonDataRDDwords.mapToPair(s -> new Tuple2<>(s, 1));
    JavaPairRDD<String, Integer> jsonDataRDDcounts = jsonDataRDDones.reduceByKey((i1, i2) -> i1 + i2);
    List<Tuple2<String, Integer>> jsonDatRDDoutput = jsonDataRDDcounts.collect();

我甚至试过telnet到Cassandra服务器端口是开放的。

我能够建立连接但是在执行reduceByKey时获得上述异常。

我无法弄清问题是什么。在javardd操作中有问题。任何帮助,将不胜感激。提前致谢。

java spring-boot apache-spark cassandra spark-cassandra-connector
1个回答
0
投票

上述错误是由于cassandra驱动核心的一些依赖性问题。通过在我的pom.xml中添加度量依赖来解决它

<dependency>
<groupId>io.dropwizard.metrics</groupId>
<artifactId>metrics-core</artifactId>
<version>3.2.2</version>
</dependency>
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