如果value小于240000
,我需要向第4列添加常量值。常数值是010000
。我写了命令,但它没有给出任何输出。以下是示例数据和脚本。请帮帮我。谢谢。
命令:
awk '{
if($4 -lt 240000)
$4= $4+010000;
}' Test.txt
样本数据 :
1039,1018,20180915,000000,0,0,A
1039,1018,20180915,010000,0,0,A
1039,1018,20180915,020000,0,0,A
1039,1018,20180915,030000,0,0,A
1039,1018,20180915,240000,0,0,A
1039,1018,20180915,050000,0,0,A
1039,1018,20180915,060000,0,0,A
1039,1018,20180915,070000,1,0,A
1039,1018,20180915,080000,0,1,A
1039,1018,20180915,090000,2,0,A
1039,1018,20180915,241000,0,0,A
1039,1018,20180915,240500,0,0,A
$ awk '
BEGIN { FS=OFS="," } # input and output field separators
{
if($4<240000) # if comparison
$4=sprintf("%06d",$4+10000) # I assume 10000 not 010000, also zeropadded to 6 chars
# $4+=10000 # if zeropadding is not required
print # output
}' file
输出:
1039,1018,20180915,010000,0,0,A
1039,1018,20180915,020000,0,0,A
1039,1018,20180915,030000,0,0,A
1039,1018,20180915,040000,0,0,A
1039,1018,20180915,240000,0,0,A
1039,1018,20180915,060000,0,0,A
1039,1018,20180915,070000,0,0,A
1039,1018,20180915,080000,1,0,A
1039,1018,20180915,090000,0,1,A
1039,1018,20180915,100000,2,0,A
1039,1018,20180915,241000,0,0,A
1039,1018,20180915,240500,0,0,A
qazxsw poi not qazxsw poi,因为qazxsw poi输出qazxsw poi,因为它是该值的八进制表示。