基于2个值选择不同行

Question

我有表像

PONO    LINESNO   status
1        10        X
1        20        X
1        30        y 
2        10        X
2        20        X
2        30        X

在这里，在这个表中我们有对用不同的状态，为每个LINESNO 2 PO 2个独特PO数字1和2。我想编写一个查询只返回所有LINESNO具有同等的地位e.g如果我在传递状态PO Where子句“Where Status='X'”，那么它应该与PO 2，因为PO2让所有LINESNO与X相同的状态只返回一行

<table>
  <tr>
    <td>
      PO NO
    </td>
    <td>
      LINENO
    </td>
    <td> Status</td>
  </tr>
  <tr>
    <td> 1 </td>
    <td> 10 </td>
    <td> X</td>
  </tr>
  <tr>
    <td> 1 </td>
    <td> 20 </td>
    <td> X</td>
  </tr>
  <tr>
    <td> 1 </td>
    <td> 30 </td>
    <td> Y</td>
  </tr>
  <tr>
    <td> 2 </td>
    <td> 10 </td>
    <td> X</td>
  </tr>
  <tr>
    <td> 2 </td>
    <td> 20 </td>
    <td> X</td>
  </tr>
  <tr>
    <td> 3 </td>
    <td> 30 </td>
    <td> X</td>
  </tr>
</table>

Answer 1

我想这可能是工作：

架构（MySQL的V5.7）

create table pos (pono int, LINESNO int, status varchar(1));
insert into pos values (1, 10, 'x');
insert into pos values (1, 20, 'x');
insert into pos values (1, 30, 'y');
insert into pos values (2, 10, 'x');
insert into pos values (2, 20, 'x');
insert into pos values (2, 30, 'x');
insert into pos values (3, 20, 'x');
insert into pos values (3, 30, 'y');
insert into pos values (4, 30, 'x');

---

查询＃1

Select a.pono, a.total_pono, b.total_status from
(select pono, count(*) as total_pono from pos group by pono) a,
(select pono, count(*) as total_status from pos where status = 'x' group by pono) b
where a.total_pono = b.total_status
and a.pono = b.pono;

| pono | total_pono | total_status |
| ---- | ---------- | ------------ |
| 2    | 3          | 3            |
| 4    | 1          | 1            |

---

View on DB Fiddle