我正在使用Django 2.0和Python 3.7。我有这个模型和经理,试图通过名称(大小写)找到我的模型。支持数据库是MySql 5.7。
class CoopManager(models.Manager):
...
# Look up coops by a partial name (case insensitive)
def find_by_name(self, partial_name):
queryset = Coop.objects.filter(name__icontains=partial_name, enabled=True)
print(queryset.query)
return queryset
class Coop(models.Model):
objects = CoopManager()
name = models.CharField(max_length=250, null=False)
type = models.ForeignKey(CoopType, on_delete=None)
address = AddressField(on_delete=models.CASCADE)
enabled = models.BooleanField(default=True, null=False)
phone = PhoneNumberField(null=True)
email = models.EmailField(null=True)
web_site = models.TextField()
[不幸的是,当查询实际上被创建时,看来Django并没有采取任何措施来解决不区分大小写的问题。这是一个示例查询,其结果是...
SELECT `maps_coop`.`id`, `maps_coop`.`name`, `maps_coop`.`type_id`, `maps_coop`.`address_id`, `maps_coop`.`enabled`, `maps_coop`.`phone`, `maps_coop`.`email`, `maps_coop`.`web_site` FROM `maps_coop` WHERE (`maps_coop`.`name` LIKE %res% AND `maps_coop`.`enabled` = True)
我需要进行哪些更改,以便Django以不区分大小写的方式对MySql数据库执行查询?
编辑:这是“ show create table ...”的MySql输出。
| maps_coop | CREATE TABLE `maps_coop` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(250) COLLATE utf8_bin NOT NULL,
`enabled` tinyint(1) NOT NULL,
`phone` varchar(128) COLLATE utf8_bin DEFAULT NULL,
`email` varchar(254) COLLATE utf8_bin DEFAULT NULL,
`web_site` longtext COLLATE utf8_bin NOT NULL,
`address_id` int(11) DEFAULT NULL,
`type_id` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `maps_coop_address_id_f90898f3` (`address_id`),
KEY `maps_coop_type_id_982652ce_fk_maps_cooptype_id` (`type_id`),
CONSTRAINT `maps_coop_address_id_f90898f3_fk_address_address_id` FOREIGN KEY (`address_id`) REFERENCES `address_address` (`id`),
CONSTRAINT `maps_coop_type_id_982652ce_fk_maps_cooptype_id` FOREIGN KEY (`type_id`) REFERENCES `maps_cooptype` (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=933 DEFAULT CHARSET=utf8 COLLATE=utf8_bin |
您必须将MySQL数据库/表的排序规则更改为utf8_unicode_ci
或utf_unicode_ci
;末尾的[[ci
首字母缩写为“ c ase i nsensitive”。