我创建使用ES6符号Node.js的一个端点。例
// ES6符号方法
const taskCreationMethod = {
[Symbol.taskMethod]() {
return {
storeCheckFunc: async function(storeId, employeeId) {
let store = await resourceModel["stores"].findById(storeId).populate(references["stores"]);
if(!store) {
return new Error("Store not found");
}
let employeeCheck = _.find(store.employees, (empObj) => {
return empObj._id == employeeId
})
if(!employeeCheck) {
return new Error("Employee not found");
}
return employeeCheck;
}
};
}
}
//终点
export const taskCreation = async(req, res) => {
const storeCheck = await taskCreationMethod[Symbol.taskMethod]().storeCheckFunc(req.body.store, req.body.assigned_to);
// here How can I handle return with Error Response?
}
你需要throw
该错误不只是return
它,如果你想使用的错误处理机制。抛出的错误将成为被拒绝的承诺,你可以接着用.catch()
直接在承诺或与try/catch
处理,如果你在一个异步函数中使用它。这里有一个简单的例子:
function populate() {
// always resolves to undefined
return Promise.resolve(undefined)
}
const taskCreationMethod = {
someMethod() {
return {
storeCheckFunc: async function() {
let store = await populate() // always resolves undefined
if (!store) { // so it always fails
throw new Error("Store not found"); // throw error
}
}
};
}
}
// regular promise then().catch()
taskCreationMethod.someMethod().storeCheckFunc()
.then(res => console.log(res))
.catch(err => console.log("Error:", err.message)) // catch
// OR … async function
async function runit() {
try {
let s = await taskCreationMethod.someMethod().storeCheckFunc()
} catch (err) {
console.log("Error:", err.message)
}
}
runit()