我正在尝试使一个函数在回文数为真的情况下返回true,在数字不是的情况下返回false,因此首先我创建了一个对数字进行求反的函数,然后创建另一个函数以求出反转的数字是否等于原始数。数字,但没有为我返回正确的输出,有帮助吗?
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>
//Reversing a number
int DigitsReversing(int num)
{
int resultofR = 0;
while (num > 0)
{
resultofR = resultofR * 10 + num % 10;
num = num / 10;
}
return resultofR;
}
//telling if the original number equal to the reversed number if yes return if not return false
int isPali(int num)
{
DigitsReversing(num);
int resultofR;
if (num == resultofR)
return true;
else
return false;
return 0;
}
//calling the function
int main()
{
int num;
scanf("%d", &num);
printf("%d", isPali(num));
return 0;
}
编辑的****:
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <math.h>
#include <stdbool.h>
int DigitsReversing(int num)
{
int resultofR = 0;
while (num > 0)
{
resultofR = resultofR * 10 + num % 10;
num = num / 10;
}
return resultofR;
}
bool isPali(int num , int resultofR)
{
resultofR = DigitsReversing(num);
if (num == resultofR)
return true;
else
return false;
}
int main()
{
int num, resultofR;
scanf("%d", &num);
resultofR = DigitsReversing(num);
isPali(num, resultofR);
C确实具有布尔数据类型。通常,0为假,1为真。返回值应为1表示true,0表示false。
#include<stdio.h>
#include<math.h>
//Reversing a number
int DigitsReversing(int num)
{
int resultofR = 0;
while (num > 0)
{
resultofR = resultofR * 10 + num % 10;
num = num / 10;
}
return resultofR;
}
//telling if the original number equal to the reversed number if yes return if not return false
void isPali(int num)
{
int resultofR= DigitsReversing(num);
if (num == resultofR)
printf("True");
else
printf("False");
}
//calling the function
int main()
{
int num;
scanf("%d",&num);
isPali(num);
return 0;
}
输出对于非回文数。
9998
False
--------------------------------
Process exited after 10.35 seconds with return value 0
Press any key to continue . . .
回文数。
9999
True
--------------------------------
Process exited after 10.35 seconds with return value 0
Press any key to continue . . .