使用正则表达式捕捉莎士比亚角色的对话

Question

我正在尝试使用正则表达式捕获莎士比亚对话，以便使用正则表达式进行文本匹配。例如，我想在这个特定的场景中捕获一个名为CALIBAN的角色所说的所有文字：

  PROSPERO. Thou most lying slave,
    Whom stripes may move, not kindness! I have us'd thee,
    Filth as thou art, with human care, and lodg'd thee
    In mine own cell, till thou didst seek to violate
    The honour of my child.

  CALIBAN. O ho, O ho! Would't had been done.
    Thou didst prevent me. I had peopl'd else
    This isle with Calibans.

  PROSPERO. Thou most lying slave,
    Whom stripes may move, not kindness! I have us'd thee,
    Filth as thou art, with human care, and lodg'd thee
    In mine own cell, till thou didst seek to violate
    The honour of my child.

  CALIBAN. O ho, O ho! Would't had been done.
    Thou didst prevent me. I had peopl'd else
    This isle with Calibans.

我想抓住

O ho, O ho! Would't had been done.
        Thou didst prevent me. I had peopl'd else
        This isle with Calibans.

我如何使用正则表达式来实现这一目标？我尝试了这个特殊的正则表达式：

(?<=\n  CALIBAN\. )[A-Za-z ',\.\n\!-]+(?=\n  PROSPERO\. |$)

注意：在实际文本中，总是有2个空格字符，然后是新字符的名称。每一行的末尾都有一个回车符。我的正则表达式寻找CALIBAN.开始，然后匹配一些文本，并确保它必须以PROSPERO.结束。但是，当我将其插入regexp.com时，我的整个文本都匹配：

Answer 1

你可以使用这个正则表达式与懒惰量词：

(?<=\n  CALIBAN\. )[A-Za-z\s',.!-]+?(?=\n  PROSPERO\. |$)

Updated Regex Demo

在PHP中使用：

$re = '/(?<=\n  CALIBAN\. )[A-Za-z\s\',.!-]+?(?=\n  PROSPERO\. |$)/';

preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);

// Print the result
print_r($matches[0]);

Answer 2

尝试使用以下正则表达式：

CALIBAN. ((.*\n .*)*)

第一个捕获组（组1）将匹配Caliban所说的文本而不包括他的名字。根据提供的示例，此正则表达式应该可行。