为什么这个字典的元组列表中的值没有打印出来？

Question

我试图在输入浮点字符串时打印键的值。

这是我的代码：

number_dict = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', 6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 0: 'Zero', '-': 'Negative', '.': 'Point'}

while True:
    try:
        number = input('Enter a number: ')
        float(number)
        print(f'As Text:', end = ' ')
        for char in number:
            for key, value in number_dict.items():
                if char == key:
                    print(number_dict[key], end = ' ')
                elif int(char) == key:
                    print(number_dict[key], end = ' ')
         break
    except ValueError:
        if ',' in number:
            print('Please try again without entering commas.')
        elif number.isdigit() == False  and '-' not in number and '.' not in number:
            print(f'"{number}" is not a valid number. Please try again.')

我做错了什么？为什么这些值不与“.”相关联和“-”键打印？应该在 elif 条件下访问它们。

已经有一个

try

和

except

块来解释 ValueError。我只是不想发布完整的代码，但我知道这个错误并且已经解决了。

提前感谢您的帮助！！

Answer 1

如果将所有键保留为字符串会容易得多：

number_dict = {'1': 'One', '2': 'Two', '3': 'Three', '4': 'Four', '5': 'Five', '6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine', '0': 'Zero', '-': 'Negative', '.': 'Point'}

number = input('Enter a number: ')

for char in number:
    try:
        print(number_dict[char], end = ' ')
    except KeyError:
        if ',' in number:
            print('Please try again without entering commas.')
        elif number.isdigit() == False  and '-' not in number and '.' not in number:
            print(f'"{number}" is not a valid number. Please try again.')
        break
    else:
        print()