突破循环-Python

Question

我已经尝试使用谷歌搜索和搜索，但是我无法弄清楚为什么我倒数第二行的中断没有退出while循环。更好的是，我无法弄清楚为什么循环也没有继续。我的意图是让用户有可能在最后一个选择之后进入主菜单（基本上是menuchoice的while循环（这是我在此处粘贴的循环之上的一个循环）。

有什么建议吗？先感谢您。感觉好像我缺少一些重要的东西。

#this is going to show how many exercise weapons you need for next magic level
if menuchoice == "4":
    #these functions returns the amount of magic wands/rods that is needed to be spent for next magic level
    print("Select vocation")
    print("Press P for Royal Paladin")

    #ask user to input vocation:
    while True:
        vocationchoice = input()
        if vocationchoice == "P" or vocationchoice == "p":
            #ask user to input magic level for paladin
            num1 = float (input("Enter your magic level: "))

            #ask for own training dummy
            print("Do you have your own exercise dummy? Type Y for yes and N for no.")
            while True:
                trainingdummy = input()
                if trainingdummy == "y" or trainingdummy == "Y":
                    #list the different exercise weapons
                    print("Select exercise weapon:")
                    print("1. Training rod")

                    #loop, where we ask user to input what exercise weapon they want to calculate
                    while True:
                        while True:
                            weaponchoice = input()
                            if weaponchoice == "q":
                                sys.exit() #quit the program
                            if weaponchoice == "1" or weaponchoice == "2" or weaponchoice == "3" or weaponchoice == "f":
                                break #break out of the input loop

                        #User choice
                        if weaponchoice == "1":
                            print("The amount of training rods needed for next magic level is " + str((nextmaglvlpalwithdummy(num1))) + ".")

                if trainingdummy == "n" or trainingdummy == "N":
                    #list the different exercise weapons
                    print("Select exercise weapon:")
                    print("1. Training rod")

                    #loop where ask user to input what exercise weapon they want to calculate
                    while True:
                        weaponchoice = input()
                        #User choice
                        if weaponchoice == "1":
                            print("The amount of training rods needed for next magic level is " + str((nextmaglvlpal(num1))) + ".")

                        elif weaponchoice == "f":
                            break

                        print("\nGo to main menu? Press F.")

Answer 1

首先，您应该在input()命令中打印内容，因为它将按预期清除：input("Text to display")。

第二，如果要退出主菜单，则需要中断每个嵌套循环。在这里，您只中断最内部的循环。

就像在Python中一样，没有goto指令也没有命名循环，您可以使用标志。当用户按下“ F”时，将标志设置为true，然后在每个外部嵌套循环的开头使用此标志来中断它们。它看起来可能像这样：

while True: # This is your menu loop
  menuFlag = False # Declare and set the flag to False here

  menu = input("Choose the menu: ")
  # ...

  while True: # Choose character loop
    if menuFlag: break  # Do not forget to break all outer loops   

    character = input("Choose a character: ")
    # ...

    while True: # Any other loop (choose weapon, ...)
        weapon = input("Choose weapon: ")

        # Here you want to return to the menu if f is pressed
        # Set the flag to True in this condition
        if weapon == "f":
            menuFlag = True
            break

在您的游戏中，它外观如下：

goToMainMenu = False

while True:
    if goToMainMenu: break
    vocationchoice = input("Select vocation.\nPress P for Royal Paladin: ")

    if vocationchoice == "P" or vocationchoice == "p":
        #ask user to input magic level for paladin
        num1 = float (input("Enter your magic level: "))

        #ask for own training dummy
        while True:
            if goToMainMenu: break

            trainingdummy = input("Do you have your own exercise dummy?\nType Y for yes and N for no: ")
            if trainingdummy == "y" or trainingdummy == "Y":
                #loop, where we ask user to input what exercise weapon they want to calculate
                while True:
                    while True:
                        weaponchoice = input("Select exercise weapon:\n1. Training rod: ")
                        if weaponchoice == "q":
                            sys.exit() #quit the program
                        if weaponchoice == "1" or weaponchoice == "2" or weaponchoice == "3" or weaponchoice == "f":
                            break #break out of the input loop

                    #User choice
                    if weaponchoice == "1":
                        print("The amount of training rods needed for next magic level is " + str((nextmaglvlpalwithdummy(num1))) + ".")

            if trainingdummy == "n" or trainingdummy == "N":
                #list the different exercise weapon

                #loop where ask user to input what exercise weapon they want to calculate
                while True:
                    weaponchoice = input("Select exercise weapon (press F for main menu):\n1. Training rod: ")
                    #User choice
                    if weaponchoice == "1":
                        print("The amount of training rods needed for next magic level is " + str((nextmaglvlpalwithdummy(num1))) + ".")

                    elif weaponchoice == "f" or weaponchoice == "F":
                        goToMainMenu = True
                        break

Answer 2

This我想会帮助您。中断仅从电流回路中断。如果要提高水平，则需要分别退出每个循环。

A suggestion是将循环变成函数并使用return，它将有效地退出任何循环。不过，将需要一点代码重构。

如果不是这种情况，您也许可以提供更多信息，甚至可能提供完整的代码（有一个更高的循环，我们在这里看不到？）

Answer 3

为break添加weaponchoice == "1"以退出循环。