大家好,我对如何使其更简洁,可重用和更具可读性有疑问。我有一些数据模型(相对而言),具有稀有性和水平。根据级别和稀有性,必须对其进行分组,以便稍后将其应用于某些数学计算中。因此,我需要解析所有文物,并检查其级别和稀有度并存储在var计数器中。
public double TotalGlobalBonus
{
get
{
float commonRarityMultiplier = 20;
float rareRarityMultiplier = 120;
float epicRarityMultiplier = 320;
float legendaryRarityMultiplier = 540;
int rarityCommonLevel1 = 0;
int rarityCommonLevel2 = 0;
int rarityCommonLevel3 = 0;
int rarityCommonLevel4 = 0;
int rarityCommonLevel5 = 0;
int rarityRareLevel1 = 0;
int rarityRareLevel2 = 0;
int rarityRareLevel3 = 0;
int rarityRareLevel4 = 0;
int rarityRareLevel5 = 0;
int rarityEpicLevel1 = 0;
int rarityEpicLevel2 = 0;
int rarityEpicLevel3 = 0;
int rarityEpicLevel4 = 0;
int rarityEpicLevel5 = 0;
int rarityLegendaryLevel1 = 0;
int rarityLegendaryLevel2 = 0;
int rarityLegendaryLevel3 = 0;
int rarityLegendaryLevel4 = 0;
int rarityLegendaryLevel5 = 0;
foreach (RelicModel relic in this.equipedRelics)
{
switch (relic.rarity)
{
case RarityType.COMMON:
switch (relic.Level)
{
case 1:
rarityCommonLevel1++;
break;
case 2:
rarityCommonLevel2++;
break;
case 3:
rarityCommonLevel3++;
break;
case 4:
rarityCommonLevel4++;
break;
case 5:
rarityCommonLevel5++;
break;
}
break;
case RarityType.RARE:
switch (relic.Level)
{
case 1:
rarityRareLevel1++;
break;
case 2:
rarityRareLevel2++;
break;
case 3:
rarityRareLevel3++;
break;
case 4:
rarityRareLevel4++;
break;
case 5:
rarityRareLevel5++;
break;
}
break;
case RarityType.EPIC:
switch (relic.Level)
{
case 1:
rarityEpicLevel1++;
break;
case 2:
rarityEpicLevel2++;
break;
case 3:
rarityEpicLevel3++;
break;
case 4:
rarityEpicLevel4++;
break;
case 5:
rarityEpicLevel5++;
break;
}
break;
case RarityType.LEGENDARY:
{
switch (relic.Level)
{
case 1:
rarityLegendaryLevel1++;
break;
case 2:
rarityLegendaryLevel2++;
break;
case 3:
rarityLegendaryLevel3++;
break;
case 4:
rarityLegendaryLevel4++;
break;
case 5:
rarityLegendaryLevel5++;
break;
}
break;
}
}
}
double common = (commonRarityMultiplier / 100) * (rarityCommonLevel1 * 1 + rarityCommonLevel2 * 5 +
rarityCommonLevel3 * 10 + rarityCommonLevel4 * 20 +
rarityCommonLevel5 * 40);
double rare = (rareRarityMultiplier / 100) * (rarityRareLevel1 * 1 + rarityRareLevel2 * 5 +
rarityRareLevel3 * 10 + rarityRareLevel4 * 20 +
rarityRareLevel5 * 40);
double epic = (epicRarityMultiplier / 100) * (rarityEpicLevel1 * 1 + rarityEpicLevel2 * 5 +
rarityEpicLevel3 * 10 + rarityEpicLevel4 * 20 +
rarityEpicLevel5 * 40);
double legendary = (legendaryRarityMultiplier / 100) * (rarityLegendaryLevel1 * 1 + rarityLegendaryLevel2 * 5 +
rarityLegendaryLevel3 * 10 + rarityLegendaryLevel4 * 20 +
rarityLegendaryLevel5 * 40);
double final = common + rare + epic + legendary;
return final;
}
}
这是一个真正的长寿财产,如果级别数增加,它将增加,因此无法精确缩放