如何从SOAP Logical Handler获取有效负载对象

Question

我正在学习如何在JAX-WS SOAP Web服务中创建逻辑处理程序。在这里，我试图获取有效载荷数据，并希望打印出来进行测试。但是我遇到了问题。

这是我的LogincalHandler代码

public class HelloMessengerLogicalHandler implements LogicalHandler<LogicalMessageContext> {

    public void close(MessageContext ctx) {
    }

    public boolean handleFault(LogicalMessageContext ctx) {
        return false;
    }

    public boolean handleMessage(LogicalMessageContext ctx) {
        Boolean outbound = (Boolean) ctx.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);
        if(outbound) {
            LogicalMessage message = ctx.getMessage();
            //Source payload = message.getPayload();
            JAXBContext jaxbContext;
            try {
                jaxbContext = JAXBContext.newInstance(Person.class);
                Object jaxbPayload = message.getPayload(jaxbContext);
                System.out.println(jaxbPayload);
            } catch (JAXBException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }

        return true;
    }
}

这是我的网络服务代码：

@WebService
@HandlerChain(file = "handler-chain.xml")
public class HelloMessenger {
    public Person getPerson(String name) {
        return new Person(name);
    }
}

这是我的Person课程：

public class Person {

    // Default Constructor & Getters, Setters
    private String name;

    public Person(String name) {
        this.name = name;
    }
    @Override
    public String toString() {
        return "Person [name=" + name + "]";
    }
}

当我发布我的代码并访问webservice时，我得到以下异常：

javax.xml.ws.WebServiceException: javax.xml.bind.MarshalException
 - with linked exception:
[com.sun.istack.internal.SAXParseException2; unexpected element (uri:"http://simple/", local:"getPersonResponse"). Expected elements are (none)]
    at com.sun.xml.internal.ws.handler.LogicalMessageImpl.getPayload(LogicalMessageImpl.java:121)
    at simple.HelloMessengerLogicalHandler.handleMessage(HelloMessengerLogicalHandler.java:31)
    at simple.HelloMessengerLogicalHandler.handleMessage(HelloMessengerLogicalHandler.java:1)
    at com.sun.xml.internal.ws.handler.HandlerProcessor.callHandleMessageReverse(HandlerProcessor.java:326)
    at com.sun.xml.internal.ws.handler.HandlerProcessor.callHandlersResponse(HandlerProcessor.java:197)
    at com.sun.xml.internal.ws.handler.ServerLogicalHandlerTube.callHandlersOnResponse(ServerLogicalHandlerTube.java:158)
    at com.sun.xml.internal.ws.handler.HandlerTube.processResponse(HandlerTube.java:149)
    at com.sun.xml.internal.ws.api.pipe.Fiber.__doRun(Fiber.java:636)
    at com.sun.xml.internal.ws.api.pipe.Fiber._doRun(Fiber.java:585)
    at com.sun.xml.internal.ws.api.pipe.Fiber.doRun(Fiber.java:570)
    at com.sun.xml.internal.ws.api.pipe.Fiber.runSync(Fiber.java:467)
    at com.sun.xml.internal.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:299)
    at com.sun.xml.internal.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:593)
    at com.sun.xml.internal.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:244)
    at com.sun.xml.internal.ws.transport.http.server.WSHttpHandler.handleExchange(WSHttpHandler.java:95)
    at com.sun.xml.internal.ws.transport.http.server.WSHttpHandler.handle(WSHttpHandler.java:80)
    at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:77)
    at sun.net.httpserver.AuthFilter.doFilter(AuthFilter.java:83)
    at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:80)
    at sun.net.httpserver.ServerImpl$Exchange$LinkHandler.handle(ServerImpl.java:677)
    at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:77)
    at sun.net.httpserver.ServerImpl$Exchange.run(ServerImpl.java:649)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
    at java.lang.Thread.run(Thread.java:745)

我是新手，我的理解是有效负载对象是Person，所以它应该在日志中显示person对象，但我看到了这个错误。

请解释此错误指示的内容以及如何在逻辑处理程序中获取有效内容数据？

Answer 1

Source payload = message.getPayload（）;

然后使用xmltransformation或其他方式将DomSource对象转换为字符串，它将为您提供有效负载。

Answer 2

正如@curious所说，使用

Source payload = message.getPayload();

使用xmltransformation将DomSource对象转换为字符串的示例代码如下所示：

StringWriter sw = new StringWriter();
Transformer transformer = TransformerFactory.newInstance().newTransformer();
Result output = new StreamResult( sw );
transformer.transform( payload, output );
System.out.println("Response : "+sw.toString());