如何在Alexa技能内正确使用异步函数？

Question

我对async编程非常陌生，所以原谅我的不理解，但我目前正在构建一个Alexa技能，它调用一个私人停车API。你可以调用这个API，它会给你最近的停车点。

    const getParkingSpots_Handler =  {
        canHandle(handlerInput) {
            const request = handlerInput.requestEnvelope.request;
            return request.type === 'IntentRequest' && request.intent.name === 'getParkingSpots' ;
        },
        handle(handlerInput) {
            const request = handlerInput.requestEnvelope.request;
            const responseBuilder = handlerInput.responseBuilder;
            let sessionAttributes = handlerInput.attributesManager.getSessionAttributes();

            let requestData = {
                // I can't show this sorry
                }

            let options = {
               // I can't show this sorry
            };

            // Call to the API
            const postAxios = async () => {
                try {
                    const response = await axios.post(API_URL, requestData, options);
                    return response.data.result;
                } catch(error) {
                    console.log(error);
                }
            };

            // Another function. This is where I use the data from the API response. I intent to add some code here that only picks out a number of results, sorts it by price etc. etc.
            const useTheResult = async () => {
                const result  = await postAxios();
                console.log('Response from the API:', result);
            };

            // We defined the functions above, now we need to execute them
            useTheResult();

            // This is what we will refer to the 'problem code'.
            let say = `Hello from confidientialCompany! You can park...`;
                return responseBuilder
                    .speak(say)
                    .reprompt('try again, ' + say)
                    .getResponse();
        },
    };

理想情况下，一旦我添加代码修改响应内的 useTheResult，我希望问题代码在 useTheResult 以及...为什么？因为一旦我挑出了我想要的数据并修改了它，我就会试着把说变成一个'Alexa可读'的句子，比如。

    let say = `Hello from confidentialCompany! You can park on ${roadName1}, ${roadName2} and ${roadName3}. Prices start from ${startingPrice} pounds.`

如果我现在这样做，因为它是，我得到一个错误 当测试它在Alexa控制台。我不知道该怎么做了，我感觉自己会陷入一个无限循环的异步函数中。

Answer 1

添加 async 关键字 handle 方法名称和用途 await 里面。

const getParkingSpots_Handler =  {
        canHandle(handlerInput) {
            const request = handlerInput.requestEnvelope.request;
            return request.type === 'IntentRequest' && request.intent.name === 'getParkingSpots' ;
        },
        async handle(handlerInput) {
            const request = handlerInput.requestEnvelope.request;
            const responseBuilder = handlerInput.responseBuilder;
            let sessionAttributes = handlerInput.attributesManager.getSessionAttributes();

            let requestData = {
                // I can't show this sorry
                }

            let options = {
               // I can't show this sorry
            };

            // Call to the API
             let result = null;
             try {
                 const response = await axios.post(API_URL, requestData, options);
                 result = response.data.result;
             } catch(error) {
                 // handle this case and return some message to User
                 console.log(error);
             }

            // assume your data structure to be like:
            /**
             result: {
               roadName1: "1st street",
               roadName2: "2nd street",
               roadName3: "3rd street", 
               startingPrice: "1.2"
             }
            */
            const {roadName1, roadName2, roadName3, startingPrice} = result;

            // This is what we will refer to the 'problem code'.
            let say = `Hello from confidentialCompany! You can park on ${roadName1}, ${roadName2} and ${roadName3}. Prices start from ${startingPrice} pounds.`;
                return responseBuilder
                    .speak(say)
                    .reprompt('try again, ' + say)
                    .getResponse();
        },
    };