R中data.table包中fread速度背后的原因

问题描述 投票:18回答:1

我对fread在大型数据文件上的data.table函数的速度感到惊讶,但它如何能够如此快速地读取? freadread.csv之间的基本实现差异是什么?

r performance data.table fread
1个回答
28
投票

我假设我们正在将read.csv与所有已知的建议进行比较,例如设置colClassesnrows等。没有任何其他参数的read.csv(filename)是缓慢的,主要是因为它首先将所有内容读入内存,就好像它是character然后尝试将其强制转换为integernumeric作为第二步。

那么,将freadread.csv(filename, colClasses=, nrows=, etc)进行比较......

它们都是用C语言编写的,所以不是这样。

特别是没有一个原因,但基本上,fread内存将文件映射到内存中,然后使用指针迭代文件。而read.csv通过连接将文件读入缓冲区。

如果你用fread运行verbose=TRUE它会告诉你它是如何工作的,并报告每个步骤花费的时间。例如,请注意它直接跳到文件的中间和末尾以更好地猜测列类型(尽管在这种情况下前5个就足够了)。

> fread("test.csv",verbose=TRUE)
Input contains no \n. Taking this to be a filename to open
File opened, filesize is 0.486 GB
File is opened and mapped ok
Detected eol as \n only (no \r afterwards), the UNIX and Mac standard.
Using line 30 to detect sep (the last non blank line in the first 'autostart') ... sep=','
Found 6 columns
First row with 6 fields occurs on line 1 (either column names or first row of data)
All the fields on line 1 are character fields. Treating as the column names.
Count of eol after first data row: 10000001
Subtracted 1 for last eol and any trailing empty lines, leaving 10000000 data rows
Type codes (   first 5 rows): 113431
Type codes (+ middle 5 rows): 113431
Type codes (+   last 5 rows): 113431
Type codes: 113431 (after applying colClasses and integer64)
Type codes: 113431 (after applying drop or select (if supplied)
Allocating 6 column slots (6 - 0 dropped)
Read 10000000 rows and 6 (of 6) columns from 0.486 GB file in 00:00:44
  13.420s ( 31%) Memory map (rerun may be quicker)
   0.000s (  0%) sep and header detection
   3.210s (  7%) Count rows (wc -l)
   0.000s (  0%) Column type detection (first, middle and last 5 rows)
   1.310s (  3%) Allocation of 10000000x6 result (xMB) in RAM
  25.580s ( 59%) Reading data
   0.000s (  0%) Allocation for type bumps (if any), including gc time if triggered
   0.000s (  0%) Coercing data already read in type bumps (if any)
   0.040s (  0%) Changing na.strings to NA
  43.560s        Total

注意:我的速度非常慢的上网本没有固态硬盘。每个步骤的绝对时间和相对时间在机器之间会有很大差异。例如,如果您第二次重新运行fread,您可能会注意到mmap的时间要少得多,因为您的操作系统已经从之前的运行中缓存了它。

$ lscpu
Architecture:          x86_64
CPU op-mode(s):        32-bit, 64-bit
Byte Order:            Little Endian
CPU(s):                2
On-line CPU(s) list:   0,1
Thread(s) per core:    1
Core(s) per socket:    2
Socket(s):             1
NUMA node(s):          1
Vendor ID:             AuthenticAMD
CPU family:            20
Model:                 2
Stepping:              0
CPU MHz:               800.000         # i.e. my slow netbook
BogoMIPS:              1995.01
Virtualisation:        AMD-V
L1d cache:             32K
L1i cache:             32K
L2 cache:              512K
NUMA node0 CPU(s):     0,1
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