Discord Python Bot nuke 命令部分有效

Question

所以我尝试让我的discord bot成为nuke命令，但只有nuke部分有效，取消部分不起作用。

我的代码：

import discord
from discord.ext import commands
from discord.ui import Button, View

class Channels(commands.Cog):
    def __init__(self, bot):
        self.bot = bot

    @commands.command()
    @commands.has_permissions(manage_channels=True)
    async def nuke(self, ctx, channel: discord.TextChannel = None):
        if channel is None: 
            await ctx.send(f"{ctx.author.mention}! You did not mention a channel!", delete_after=5)
            return
        nuke_channel = discord.utils.get(ctx.guild.channels, name=channel.name)
        if nuke_channel is not None:
            yes = Button(label="Yes", style=discord.ButtonStyle.green)
            no = Button(label="No", style=discord.ButtonStyle.red)
            async def yes_callback(interaction):
                if interaction.user == ctx.author:
                    new_channel = await nuke_channel.clone(reason="Has been Nuked!")
                    await nuke_channel.delete()
                    await new_channel.send(f"Nuked! {ctx.author.mention}", delete_after=0.1)
                    await new_channel.send(f"Nuked by `{ctx.author.name}`")
                    with open("logs.json", "a") as f:
                        f.writelines(f"\n{ctx.author} used the nuke command. Channel nuked: {nuke_channel.name}")
            async def no_callback(interaction):
                if interaction.user == ctx.author:
                    await nuke_channel.send("Aborted")
                    no.label = "No more pressing!" 
                    no.disabled = True  
                    await interaction.response.edit_message(view=self)
            yes.callback = yes_callback
            no.callback = no_callback
            view = View()
            view.add_item(yes)
            view.add_item(no)
            await nuke_channel.send(f"{ctx.author.mention}, are you sure you want to nuke this channel?", view=view)
        else:
            await ctx.send(f"No channel named **{channel.name}** was found!")
    @nuke.error
    async def nuke_error(self, ctx, error):
        if isinstance(error, commands.MissingPermissions):
            await ctx.send("You don't have permission to use this command.")

当我点击“是”时，一切都很顺利。但是当我单击“否”时，机器人会发送一条消息“已中止”并显示

interaction failed

但按钮仍然可以单击。我的问题是，如何在按“否”后使按钮不可点击，以及如何停止使其显示

interaction failed

。因为我已经添加了

no.disabled = True

所以我不知道出了什么问题

Answer 1

这是一种混乱，这不是推荐的发表观点的方式。我会指出你代码中的错误。

特别是这一行：

await interaction.response.edit_message(view=self)

由于这不是视图类而是齿轮，因此

self

指的是齿轮而不是视图。交互失败，因为您应该将

ui.View

实例传递给

view=

kwarg，但实际上传递的是

Cog

。

现在，推荐的制作此视图的方法如下：

class Confirm(discord.ui.View):
    def __init__(self, ctx, nuke_channel):
         self.ctx = ctx # For your condition
         self.nuke_channel = nuke_channel # So you can access it in your buttons
         super().__init__()

    @discord.ui.button(label="Yes", style=discord.ButtonStyle.green)
    async def yes_callback(self, interaction, button):
        if interaction.user == self.ctx.author:
           new_channel = await self.nuke_channel.clone(reason="Has been Nuked!")
           await self.nuke_channel.delete()
           await new_channel.send(f"Nuked! {ctx.author.mention}", delete_after=0.1)
           await new_channel.send(f"Nuked by `{ctx.author.name}`")
           with open("logs.json", "a") as f:
               f.writelines(f"\n{ctx.author} used the nuke command. Channel nuked: {self.nuke_channel.name}")

    @discord.ui.button(label="No", style=discord.ButtonStyle.red)
    async def no_callback(self, interaction, button):
        if interaction.user == self.ctx.author:
            await nuke_channel.send("Aborted")
            button.label = "No more pressing!" # the 'button' is the button being pressed
            button.disabled = True  
            await interaction.response.edit_message(view=self)

然后，在您的命令中，您可以像这样初始化视图：

view = Confirm(ctx, nuke_channel)

更简洁的代码。