如何在ArangoDB中的对象数组中对对象数组进行过滤和排序

Question

嗨，我的有效载荷如下：

{
  "Id": "3",
  "List": {
    "Steps": [
      {
        "StepId": "1",
        "stepDesc1": [
          {
            "sortNo": "2",
            "description": "ABC"
          },
          {
            "sortNo": "1",
            "description": "XYZ"
          }
        ],
        "stepDesc2": [
          {
            "sortNo": "2",
            "description": "AAA"
          },
          {
            "sortNo": "1",
            "description": "BBB"
          }
        ]
      },
      {
        "StepId": "2",
        "stepDesc1": [
          {
            "sortNo": "2",
            "description": "CCC"
          },
          {
            "sortNo": "1",
            "description": "DDD"
          }
        ],
        "stepDesc2": [
          {
            "sortNo": "2",
            "description": "EEE"
          },
          {
            "sortNo": "1",
            "description": "FFF"
          }
        ]
      }
    ]
  }
}

我想按Id和StepId进行过滤，并按SortNo排序并返回数据

我已在下面的查询中使用ID和StepId进行过滤

FOR test IN test_data
FILTER test.Id=='3' 
FILTER '1' IN test.List.Steps[*].StepId
SORT test.List.Steps[*].stepDesc1.sortNo ASC
RETURN test.Steps

但是第二个过滤器条件不起作用，并且返回与ID 3相对应的所有步骤。对于我来说，它应该返回到o / p以下

{
        "StepId": "1",
        "stepDesc1": [
          {
            "sortNo": "2",
            "description": "ABC"
          },
          {
            "sortNo": "1",
            "description": "XYZ"
          }
        ],
        "stepDesc2": [
          {
            "sortNo": "2",
            "description": "AAA"
          },
          {
            "sortNo": "1",
            "description": "BBB"
          }
        ]
      }

任何人都可以帮我解决问题的方法

Answer 1

我相信您正在寻找的是这样的东西。因为您要应用的第二个FILTER为true，所以1确实在数组中，但是AQL并不排除2。只是说1必须存在。如果循环嵌套数组，则可以使用==。希望这可以帮助。

FOR test IN test_data
   FILTER test.Id == '3' 
    FOR step IN test.List.Steps
        FILTER step.StepId == '1' 
        SORT step[*].stepDesc1.sortNo ASC

RETURN step