['1C', '2H']
Showing the total and seperating the cards
Here is the first file that manages the game and the other is the cards
Here is the other file but the task says i cant mod it,, i just added it to make it a little easier to understand
answer has been solved test if the code works
import playing_cards
import random
player_hand = []
dealers_hand = []
#
# Testing code for step 1
##card = playing_cards.deal_one_card()
##print(card)
# Player
# Deal first card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
player_hand.append(card)
# Deal second card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
player_hand.append(card)
#ADDING UP BOTH CARDS
# Display the player's hand to the screen using a simple print statement
print("Player's hand is ", player_hand)
#Stage 3 - dealer
# Deal first card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
dealers_hand.append(card)
# Deal second card
card = playing_cards.deal_one_card()
# Append it to the player_hand list
dealers_hand.append(card)
# Display the player's hand to the screen using a simple print statement
print(dealers_hand)
You just have to write a function to convert
deck = ['AH','2H','3H','4H','5H','6H','7H','8H','9H','TH','JH','QH','KH',
'AD','2D','3D','4D','5D','6D','7D','8D','9D','TD','JD','QD','KD',
'AS','2S','3S','4S','5S','6S','7S','8S','9S','TS','JS','QS','KS',
'AC','2C','3C','4C','5C','6C','7C','8C','9C','TC','JC','QC','KC']
# Playing deck in use
playing_deck = []
# Function to determine whether there are any cards left in the
# deck of playing cards
# Parameters: No parameters
# Returns: True if the deck is empty, False otherwise
def is_empty_deck():
# Check to see whether playing deck is empty
return len(playing_deck) == 0
# Function to rebuild and shuffle the deck
# Parameters: No parameters
# Returns: Nothing is returned from the function.
def reset_deck():
global playing_deck
# Create new playing deck
playing_deck = deck.copy()
# Shuffle deck
random.shuffle(playing_deck)
# Function to deal one card
# Parameters: No parameters
# Returns: A string (containing two characters) representing
# the card delt, i.e. '2H' meaning 2 of Hearts
def deal_one_card():
# Check to see whether there are any cards left
if is_empty_deck():
# Rebuild and shuffle deck
reset_deck()
# Return a card (string of two characters)
return playing_deck.pop(0)
1CA 1 of Club helps here, tremendously:
d = dict()
domain = ['C', 'H', 'D', 'S']
image = ['Club', 'Heart', 'Diamond', 'Spade']
for i in range(4):
d[domain[i]] = image[i]
def process(x):
return x[0] + ' of ' + d[x[1]]
print(process('1C'))
OR:dict
def card(code):
ref = {'C': 'Club', 'H': 'Heart', 'D': 'Diamond', 'S': 'Spade'}
value = {'A': 'Ace', '2': 'Two', '3': 'Three', '4': 'Four', '5': 'Five',
'6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine', 'T': 'Ten',
'J': 'Jack', 'Q': 'Queen', 'K': 'King'}
return value[code[0]] + ' of ' + ref[code[-1]]
[print(card(i)) for i in deck]
Make adjustment with Ace when hand > 21.
Ace of Hearts
Two of Hearts
Three of Hearts
Four of Hearts
Five of Hearts
Six of Hearts
Seven of Hearts
Eight of Hearts
... ...
Nine of Clubs
Ten of Clubs
Jack of Clubs
Queen of Clubs
King of Clubs
import inflect
deck = ['AH','2H','3H','4H','5H','6H','7H','8H','9H','TH','JH','QH','KH',
'AD','2D','3D','4D','5D','6D','7D','8D','9D','TD','JD','QD','KD',
'AS','2S','3S','4S','5S','6S','7S','8S','9S','TS','JS','QS','KS',
'AC','2C','3C','4C','5C','6C','7C','8C','9C','TC','JC','QC','KC']
def card(code):
ref = {'C': 'Clubs', 'H': 'Hearts', 'D': 'Diamonds', 'S': 'Spades',
'A': 'Ace', 'T': 'Ten', 'J': 'Jack', 'Q': 'Queen', 'K': 'King'}
if code[0] not in [str(i) for i in range(1, 10)]:
return ref[code[0]] + ' of ' + ref[code[-1]]
return inflect.engine().number_to_words(int(code[0])) + ' of ' + ref[code[-1]]
[print(card(i)) for i in deck]
Example hands
Output
def score_hand(player_hand):
" Scores hand with adjustment for Ace "
value = {}
for i in range(10):
value[str(i)] = i
value['J'] = 10
value['Q'] = 10
value['K'] = 10
value['A'] = 11
score = sum(int(value[card[0]]) for card in player_hand)
if score > 21:
# Adjust for Aces
adjustment = sum(10 if card[0]=='A' else 0 for card in player_hand)
score -= adjustment
return score
def show_hand(player_hand):
suits = {'C': 'Club', 'H': 'Heart', 'D': 'Diamond', 'S': 'Spade'}
names = {'2': 'Two', '3': 'Three', '4': 'Four',
'5':'Five', '6': 'Six', '7': 'Seven', '8': 'Eight', '9': 'Nine', 'T': 'Ten','J': 'Jack', 'Q': 'Queen', 'K': 'King', 'A': 'Ace'}
score = f"Player's hand is {score_hand(player_hand)}: "
cards = ' | '.join([f"{names[card[0]]} of {suits[card[1]]}" for card in player_hand])
return score + cards
我有一个黑杰克游戏，我需要做，它分为2个文件，一个是关于洗牌，另一个是关于实际的游戏。
我的问题是，我可以得到代码来打印玩家和庄家的两张牌，尽管我需要以这样的格式打印。
hands = [['3S', '4H'], ['AC', '5D'], ['AC', 'KD', '2C'], ['AC', 'KD', '5C', 'AH'], ['AC', 'AH', 'AD', 'KD', '5C'], ['AC', 'AH', 'AD', 'KD', 'JC']]
for hand in hands:
print(f"{hand} shows as ->>>>")
print(show_hand(hand))
print()
闲家的牌是3：梅花1。