基于财政年度对象的排序对象

Question

我想分类 月年Obj 基于 财务年限

var financeYears = 
[{"month":4,"year":2019,"resourceType":"Employee"},
{"month":5,"year":2019,"resourceType":"Employee"},
{"month":6,"year":2019,"resourceType":"Employee"},
{"month":7,"year":2019,"resourceType":"Employee"},
{"month":8,"year":2020,"resourceType":"Employee"},
{"month":9,"year":2020,"resourceType":"Employee"},
{"month":10,"year":2020,"resourceType":"Employee"},
{"month":11,"year":2020,"resourceType":"Employee"},
{"month":12,"year":2020,"resourceType":"Employee"},
{"month":1,"year":2020,"resourceType":"Employee"},
{"month":2,"year":2020,"resourceType":"Employee"},
{"month":3,"year":2020,"resourceType":"Employee"}]

var monthYearObj = 
[{"monthStart":1,"yearStart":2020},
{"monthStart":2,"yearStart":2020},
{"monthStart":3,"yearStart":2020},
{"monthStart":4,"yearStart":2019},
{"monthStart":5,"yearStart":2019},
{"monthStart":6,"yearStart":2019},
{"monthStart":7,"yearStart":2019},
{"monthStart":8,"yearStart":2020},
{"monthStart":9,"yearStart":2020},
{"monthStart":10,"yearStart":2020},
{"monthStart":0,"yearStart":0},
{"monthStart":0,"yearStart":0}];

并希望输出如下，并代替 {"monthStart":0,"yearStart":0} 本该 {"monthStart":11,"yearStart":2020} 和 {"monthStart":12,"yearStart":2020} 分别基于financialYears对象，因为这里缺少这两个月的数据。

var finalObject = [
{"monthStart":4,"yearStart":2019},
{"monthStart":5,"yearStart":2019},
{"monthStart":6,"yearStart":2019},
{"monthStart":7,"yearStart":2019},
{"monthStart":8,"yearStart":2020},
{"monthStart":9,"yearStart":2020},
{"monthStart":10,"yearStart":2020}
{"monthStart":11,"yearStart":2020}
{"monthStart":12,"yearStart":2020}
{"monthStart":1,"yearStart":2020},
{"monthStart":2,"yearStart":2020},
{"monthStart":3,"yearStart":2020}];

试着用下面的排序功能，但似乎没有达到预期的效果。

       monthYearObj.sort(function (a, b) {
        if (a.yearStart < b.yearStart ){
          return -1;
        } if (a.yearStart > b.yearStart){
            return 1;
        } 

        if (a.monthStart < b.monthStart ){
          return -1;
        } if (a.monthStart > b.monthStart){
            return 1;
        }

      });

所以现在我想根据financeYears来排序。

Answer 1

你可以取一个对象作为值，并按顺序映射存储的值或用给定的数据创建一个新的对象。

var financeYears = [{ month: 4, year: 2019, resourceType: "Employee" }, { month: 5, year: 2019, resourceType: "Employee" }, { month: 6, year: 2019, resourceType: "Employee" }, { month: 7, year: 2019, resourceType: "Employee" }, { month: 8, year: 2020, resourceType: "Employee" }, { month: 9, year: 2020, resourceType: "Employee" }, { month: 10, year: 2020, resourceType: "Employee" }, { month: 11, year: 2020, resourceType: "Employee" }, { month: 12, year: 2020, resourceType: "Employee" }, { month: 1, year: 2020, resourceType: "Employee" }, { month: 2, year: 2020, resourceType: "Employee" }, { month: 3, year: 2020, resourceType: "Employee" }],
    monthYearObj = [{ monthStart: 1, yearStart: 2020 }, { monthStart: 2, yearStart: 2020 }, { monthStart: 3, yearStart: 2020 }, { monthStart: 4, yearStart: 2019 }, { monthStart: 5, yearStart: 2019 }, { monthStart: 6, yearStart: 2019 }, { monthStart: 7, yearStart: 2019 }, { monthStart: 8, yearStart: 2020 }, { monthStart: 9, yearStart: 2020 }, { monthStart: 10, yearStart: 2020 }, { monthStart: 0, yearStart: 0 }, { monthStart: 0, yearStart: 0 }],
    order = monthYearObj .reduce((r, o, i) => {
        if (!o.monthStart) r[o.monthStart + '|' + o.yearStart] = o;
        return r;
    }, {}),
    result = financeYears.map(({ month, year }) => order[month + '|' + year] || { monthStart: month, yearStart: year });

monthYearObj.sort((a, b) => order[a.yearStart + '|' + a.monthStart] - order[b.yearStart + '|' + b.monthStart]);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

你的排序函数应该 return 0 在底部，因为这两个元素是相等的。另外，你根本没有使用你的financeYears对象，你只是按年月排序。