假设
Pin<&mut T>
已初始化,如何从 Pin<&mut MaybeUninit<T>>
安全地获取 MaybeUninit<T>
?
Pin::map_unchecked_mut
应该是安全的:
let pin_uninit_t: Pin<&mut MaybeUninit<T>> = ...;
let pin_t: Pin<&mut T> = unsafe { pin_uninit_t.map_unchecked_mut(|m| m.assume_init_mut()) };