嗨,我正在使用Laravel 4,我有三个模型,Project
(表名projects
),Status
(表名:statuses
)和AssignedProjectBoardStatus
(表名:assigned_project_board_statuses
)。现在,当我创建项目时,如果未从列表中选择状态,则会自动分配状态。 assigned_project_board_statuses
表有两个外键,表模式如下:
id|project_id|status_id|order|created_at|updated_at
project_id
和status_id
是外键。现在我有一个模型:
app/models/AssignedProjectBoardStatus.php
class AssignedProjectBoardStatus extends AbstractModel {
public function projects() {
return $this->belongsTo('Project');
}
public function statuses() {
return $this->belongsTo('Status');
}
}
app/models/Project.php
class Project extends AbstractModel
{
public function assignedProjectBoardStatus() {
return $this->hasMany('AssignedProjectBoardStatus');
}
app/models/Status.php
class Status extends AbstractModel {
public function assignedProjectBoardStatus() {
return $this->hasMany('AssignedProjectBoardStatus');
}
当我获取项目并且我想看到分配的状态时,我会将其称为如下:
Project::assignedScrumBoardStatuses();
但是,这会引发以下错误:
Non-static method Project::assignedProjectBoardStatuses() should not be called statically, assuming $this from incompatible context
所以我改变了如下功能:
app/models/Project.php
class Project extends AbstractModel
{
public **static** function assignedProjectBoardStatus() {
return $this->hasMany('AssignedProjectBoardStatus');
}
但是,这会引发以下错误:
Using $this when not in object context
所以我然后改变了如下功能:
public **static** function assignedScrumBoardStatuses() {
return **static::**hasMany('AssignedScrumBoardStatus');
}
然后这就抛出了这个错误:
Non-static method Illuminate\Database\Eloquent\Model::hasMany() should not be called statically
任何想法我做错了什么以及如何从模型中获得指定的状态?
你不能调用Project::assignedScrumBoardStatuses()
,因为当你这样做时,Project
模型不知道你试图获取指定的scrum board状态的记录。它没有背景。
相反,找到一个记录,以便你有一个模型实例,然后你可以调用你的关系方法:
$project = Project::find($id)->assignedScrumBoardStatuses();