我想沿着上传图片的路径一些文字在PHP MySQL数据库,我应该如何使用move_uploaded_file
与SQL语句一起?
我试着移动旁边的语句move_uploaded file
。虽然无论我尝试,只有文本将被保存在数据库中,而不是图像路径。我的代码是这样的:
<?php
if (isset($_POST['listpost-submit'])) {
$target = "site_images/";
$target2 = $target. basename($_FILES['image_file']['name']);
$title = $_POST['title'];
$description = $_POST['description'];
$price = $_POST['price'];
$cat = $_POST['categories'];
$vendor = $_POST['vendor'];
elseif (move_uploaded_file($_FILES['image_file']['name'], $target2)) {
//Database connection
require 'dbh2.inc.php';
$sql = "INSERT INTO listings
(`image`,`title`,`description`,`price`,`category`,`vendor`)
VALUES (?, ?, ?, ?, ?, ?)";
$stmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt, $sql)) {
header("Location: ../listing1.php?error=sqlerror");
exit();
}
else {
mysqli_stmt_bind_param($stmt, "ssssss", $image, $title,
$description, $price, $cat, $vendor);
mysqli_stmt_execute($stmt);
mysqli_stmt_store_result($stmt);
header("Location: ../index.php?listing=posted");
exit();
}
}
else {
header("Location: ../listing1.php?file=notuploaded");
exit();
}
}
else {
header("Location: ../listing1.php");
exit();
}
mysqli_stmt_close($stmt);
mysqli_close($conn);
我希望我所有的数据库中的列来填充,但唯一缺少的东西,当然,图像列,我想知道这是为什么,给定的信息。
如果使用的名称保存在$图像文件中
if(!empty($_FILES['image_file']['name'])
$image = $_FILES['image_file']['name'];
在表单标签您使用enctype='multipart/form-data'>"
?
<form action="" method="post" enctype="multipart/form-data">