在iOS中轻按“触摸以返回通话”

Question

是否可以检测用户是否轻按了“触摸返回通话”（https://i.stack.imgur.com/9m9xi.jpg）？可能是某种委托方法，或类似application(_:didFinishLaunchingWithOptions:)

中的参数

Answer 1

class ViewController: UIViewController {

    private var observer: NSObjectProtocol?

    override func viewDidLoad() {
        super.viewDidLoad()

        observer = NotificationCenter.default.addObserver(forName: UIApplication.willEnterForegroundNotification, object: nil, queue: .main) { [unowned self] notification in
            // do whatever you want when the app is brought back to the foreground
        }
    }
}

只需在您的callKit viewcontroller类中使用此代码，然后通过点按“触摸以返回通话”来检查用户何时返回应用程序即可