如何从嵌套对象数组的第二级对象中过滤出键

问题描述 投票:0回答:1

我正在尝试从嵌套的对象数组中过滤出一个键,在本例中为

count

我有

let test  = [
 {
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
   "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
    "index": 0,
    "value": "Bob",
    "label": "Bob",
    "count": 1
   },
   "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
    "index": 1,
    "value": "Student",
    "label": "Student",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
    "index": 2,
    "value": "BBB",
    "label": "BBB",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
    "index": 3,
    "value": "Orange Duck",
    "label": "Orange Duck",
    "count": 1
   }
  }
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
 }
]

 test = test.filter(item => item[0].options['count']);

但我越来越

Cannot read properties of undefined

我正在尝试从具有选项的所有测试元素中过滤掉计数

期望的输出是

谢谢

[
 {
  "id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8",
  "label": "Sector2",
  "options": {
   "62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {
    "index": 0,
    "value": "Bob",
    "label": "Bob"
   },
   "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {
    "index": 1,
    "value": "Student",
    "label": "Student"
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {
    "index": 2,
    "value": "BBB",
    "label": "BBB",
    "count": 1
   },
   "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {
    "index": 3,
    "value": "Orange Duck",
    "label": "Orange Duck"
   }
  }
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485",
  "label": "Brown Cow"
 },
 {
  "id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ",
  "label": "Red Fish"
 }
]
javascript arrays object google-apps-script filter
1个回答
0
投票

filter()
用于过滤数组的一部分,而不是删除对象的嵌套键。


达到您想要的结果的最简单方法是:

  1. 循环每个对象
  2. 如果这个物体有
    options
  3. 循环每个
    options
  4. 使用
    delete
    删除当前对象的
    count

const data = [{"id": "c3c6f410f58e5836431b473ebcf134756232d04f2bf35edff8", "label": "Sector2", "options": {"62f92fab79ac81d933765bd0bbc4a1f5ea26cb3a088bcb4e6e": {"index": 0, "value": "Bob", "label": "Bob", "count": 1 }, "2fe91aa3567c0d04c521dcd2fc7e40d7622bb8c3f594d503da": {"index": 1, "value": "Student", "label": "Student", "count": 1 }, "c59ea1159f33b91a7f6edc6925be5e373fc543e4": {"index": 2, "value": "BBB", "label": "BBB", "count": 1 }, "c59ea1159f33b91a7f6edc6925be5e373fc54AAA": {"index": 3, "value": "Orange Duck", "label": "Orange Duck", "count": 1 } } }, {"id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e951709485", "label": "Brown Cow" }, {"id": "f794c6a52e793ee6f5c42cd5df6b4435236e3495e95170ZZZ", "label": "Red Fish" } ];

for (let i in data) {
    if (data[i]?.options) {
        for (let j in data[i].options) {
            delete data[i].options[j]?.count;
        }
    }
}

console.log(data);

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