我正在使用django-filter
程序包在我的列表视图中提供搜索功能。
现在,我也想向该视图添加分页。我正在尝试将分页与过滤后的查询集结合起来,但是我不知道如何继续。
到目前为止,我已经在django-filter
上尝试了以下方法:
views.py
要使用Django过滤器并对过滤结果进行分页,您可以执行以下操作:
为模型创建过滤器类:
在def search(request):
qs = local_url.objects.filter(global_url__id=1).all()
paginator = Paginator(qs, 25)
page = request.GET.get('page')
try:
pub = paginator.page(page)
except PageNotAnInteger:
pub = paginator.page(1)
except EmptyPage:
pub = paginator.page(paginator.num_pages)
url_filter = PublicationFilter(request.GET, queryset=qs)
return render(request, 'ingester/search_list.html', {'filter': url_filter, 'publication':pub})
上:
my_project/my_app/filters.py
每个import django_filters
class MyModelFilter(django_filters.FilterSet):
class Meta:
model = MyModel
# Declare all your model fields by which you will filter
# your queryset here:
fields = ['field_1', 'field_2', ...]
对象都有一个FilterSet
属性,其中包含过滤的查询集,甚至可以[.qs
。
我们将分页override it if you want的.qs
属性:
在MyModelFilter
上:
my_project/my_app/views.py
就在那里!
from . import filters
from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
def my_view(request):
# BTW you do not need .all() after a .filter()
# local_url.objects.filter(global_url__id=1) will do
filtered_qs = filters.MyModelFilter(
request.GET,
queryset=MyModel.objects.all()
).qs
paginator = Paginator(filtered_qs, YOUR_PAGE_SIZE)
page = request.GET.get('page')
try:
response = paginator.page(page)
except PageNotAnInteger:
response = paginator.page(1)
except EmptyPage:
response = paginator.page(paginator.num_pages)
return render(
request,
'your_template.html',
{'response': response}
)
。PS_2:如果您要使用DRF,我已经写了一个示例,说明如何在基于函数的视图中使用分页,可以轻松地与"plays" better with Django Rest Framework结合使用:
FilterSet
这对我有用:在我的模板中,而不是使用此
@api_view(['GET',])
def my_function_based_list_view(request):
paginator = PageNumberPagination()
filtered_set = filters.MyModelFilter(
request.GET,
queryset=MyModel.objects.all()
).qs
context = paginator.paginate_queryset(filtered_set, request)
serializer = MyModelSerializer(context, many=True)
return paginator.get_paginated_response(serializer.data)
我写了这个:
<li><a href="?page={{ i }}">{{ i }}</a></li>
我希望这会有所帮助:)
这里最重要的部分是[如何在模板中构造URL。
您可能有
{% if 'whatever_parameter_you_use_to_filter' in request.get_full_path %}
<li><a href="{{ request.get_full_path }}&page={{ i }}"{{ i }}</a></li>
{% else %}
<li><a href="?page={{ i }}">{{ i }}</a></li>
{% endif %}
如果仅使用它在初始分页结果之间进行切换,那将是非常好的。
但是棘手的部分是,当您使用{% if pages.has_previous %}
<li><a href="?page={{ pages.previous_page_number }}">Prev</a></li>
{% endif %}
过滤器时,查询字符串(在'?'之后的那部分将获得全新的键值对,而忽略了django-fitler
或类似的字符。
因此,要使分页与过滤后的结果一起使用,当单击“下一步”或“上一步”按钮时-?page=2
的键值中,还需要将django-fitler
成对传递。
如@stathoula所述,您需要检查查询字符串中是否已经存在至少一个过滤器字段。如果是,那么您需要使用已经存在的键值对,然后使用新的&page=5
对。
[这似乎很简单,但是我不得不做一些小小的改动,以免在用户单击箭头时在查询字符串中一遍又一遍地重复&page=3
。
就我而言,我使用'title'作为过滤器,因此我需要检查它是否已经存在。
这是我为我的项目所做的完美工作的摘要。
templates / pagination.html
&page=1
这里是视图,以防万一:
app / views.py
<div class="paginator">
{% with request.get_full_path as querystring %}
<ul class="pagination nav navbar-nav">
<!-- Previous page section -->
{% if pages.has_previous %}
{% if 'title' in querystring %}
{% if 'page' in querystring %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring|slice:":-7" }}&page={{ pages.previous_page_number }}">Prev</a>
</li>
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring }}&page={{ pages.previous_page_number }}">Prev</a>
</li>
{% endif %}
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="?page={{ pages.previous_page_number }}">Prev</a>
</li>
{% endif %}
{% endif %}
<!-- All pages section -->
{% for page in pages.paginator.page_range %}
{% if 'title' in querystring %}
{% if 'page' in querystring %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring|slice:":-7" }}&page={{ page }}">{{ page }}</a>
</li>
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring }}&page={{ page }}">{{ page }}</a>
</li>
{% endif %}
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="?page={{ page }}">{{ page }}</a>
</li>
{% endif %}
{% endfor %}
<!-- Next page section -->
{% if pages.has_next %}
{% if 'title' in querystring %}
{% if 'page' in querystring %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring|slice:":-7" }}&page={{ pages.next_page_number }}">Next</a>
</li>
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="{{ querystring }}&page={{ pages.next_page_number }}">Next</a>
</li>
{% endif %}
{% else %}
<li class="paginator {% if pages.number == page %}active{% endif %}">
<a href="?page={{ pages.next_page_number }}">Next</a>
</li>
{% endif %}
{% endif %}
</ul>
{% endwith %}
</div>
这是一个工作示例:
。
[我花了一些时间找到DRYer和更清洁的解决方案来解决此问题,我认为最好的解决方案是使用模板标签的解决方案。
def index(request):
condo_list = Condo.objects.all().order_by('-timestamp_created')
condo_filter = CondoFilter(request.GET, queryset=condo_list)
paginator = Paginator(condo_filter.qs, MAX_CONDOS_PER_PAGE)
page = request.GET.get('page')
try:
condos = paginator.page(page)
except PageNotAnInteger:
condos = paginator.page(1)
except EmptyPage:
condos = paginator.page(paginator.num_pages)
return render(request, 'app/index.html', {
'title': 'Home',
'condos': condos,
'page': page,
'condo_filter': condo_filter,
})
以及您的模板中
from django import template
register = template.Library()
@register.simple_tag
def relative_url(value, field_name, urlencode=None):
url = '?{}={}'.format(field_name, value)
if urlencode:
querystring = urlencode.split('&')
filtered_querystring = filter(lambda p: p.split('=')[0] != field_name, querystring)
encoded_querystring = '&'.join(filtered_querystring)
url = '{}&{}'.format(url, encoded_querystring)
return url
来源:<a href="{% relative_url i 'page' request.GET.urlencode %}">{{ i }}</a>
据我所知,您的目标是对已过滤的查询集进行分页。如果是这样,则可以将PublicationFilter对象的“ qs”属性传递给Paginator构造函数:
Dealing With QueryString Parameters
url_filter.qs包含已过滤的QuerySeturl_filter.queryset包含未过滤的QuerySet
[要添加到答案中,我也使用html表以及django-filters和Paginator。以下是我的视图和模板文件。需要使用模板标记,以确保您将正确的参数传递给分页网址。
search_view.py
def search(request):
qs = local_url.objects.filter(global_url__id=1).all()
url_filter = PublicationFilter(request.GET, queryset=qs)
paginator = Paginator(url_filter.qs, 25)
page = request.GET.get('page')
try:
pub = paginator.page(page)
except PageNotAnInteger:
pub = paginator.page(1)
except EmptyPage:
pub = paginator.page(paginator.num_pages)
url_filter = PublicationFilter(request.GET, queryset=qs)
return render(request, 'ingester/search_list.html', {'publication':pub})
status_template.html
from django.shortcuts import render
from app.models.filters_model import ApiStatusFilter
from app.models.api_status import ApiStatus
from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
from datetime import datetime, timedelta
def status(request):
all_entries_ordered = ApiStatus.objects.values().order_by('-created_at')[:200]
for dictionarys in all_entries_ordered:
dictionarys
apistatus_list = ApiStatus.objects.values().order_by('-created_at')
apistatus_filter = ApiStatusFilter(request.GET, queryset=apistatus_list)
paginator = Paginator(apistatus_filter.qs, 10)
page = request.GET.get('page')
try:
dataqs = paginator.page(page)
except PageNotAnInteger:
dataqs = paginator.page(1)
except EmptyPage:
dataqs = paginator.page(paginator.num_pages)
return render(request, 'status_page_template.html', {'dictionarys': dictionarys, 'apistatus_filter': apistatus_filter, 'dataqs': dataqs, 'allobjects': apistatus_list})
my_templatetags.py
{% load static %}
{% load my_templatetags %}
<!DOCTYPE html>
<html lang="en">
<head>
<link rel="stylesheet" type="text/css" href="{% static 'css/table_styling.css' %}">
<meta charset="UTF-8">
<title>TEST</title>
</head>
<body>
<table>
<thead>
<tr>
{% for keys in dictionarys.keys %}
<th>{{ keys }}</th>
{% endfor %}
</tr>
</thead>
<form method="get">
{{ apistatus_filter.form.as_p }}
<button type="submit">Search</button>
{% for user in dataqs.object_list %}
<tr>
<td>{{ user.id }}</td>
<td>{{ user.date_time }}</td>
<td>{{ user.log }}</td>
</tr>
{% endfor %}
</form>
</tbody>
</table>
<div class="pagination">
<span>
{% if dataqs.has_previous %}
<a href="?{% query_transform request page=1 %}">« first</a>
<a href="?{% query_transform request page=dataqs.previous_page_number %}">previous</a>
{% endif %}
<span class="current">
Page {{ dataqs.number }} of {{ dataqs.paginator.num_pages }}.
</span>
{% if dataqs.has_next %}
<a href="?{% query_transform request page=dataqs.next_page_number %}">next</a>
<a href="?{% query_transform request page=dataqs.paginator.num_pages %}">last »</a>
{% endif %}
</span>
</div>
</body>
</html>