Laravel查询生成器与连接

问题描述 投票:0回答:1

我挡在我的原始SQL查询来laravel查询生成器的转换。能有人给我一只手的问题?

select p.name, p.`type`, p.`status`, p.state, ps1.* from pos_session ps1 right join pos p on ps1.pos_id = p.id where ps1.id = (select max(ps0.id) from pos_session ps0 where ps0.pos_id = ps1.pos_id) or p.site_id = '2' order by ps1.pos_id;
php laravel-5
1个回答
0
投票

试试下面的查询:

 DB::table('pos_session AS ps1')
        ->select('p.name','p.type','p.status','p.state','ps1.*')
        ->rightJoin('pos AS p','ps1.pos_id','=','p.id')
        ->where('ps1.id','=',function($query){
            $query->select(DB::raw('MAX(ps0.id)'))
                ->from('pos_session AS ps0')
                ->where('ps0.pos_id','=','ps1.pos_id');
        })
        ->orWhere('p.site_id','=',2)
        ->orderBy('ps1.pos_id')
        ->get();

你能达到的结果通过加入以及:

DB::table('pos_session AS ps1')
            ->select('p.name','p.type','p.status','p.state','ps1.*')
            ->rightJoin('pos AS p','ps1.pos_id','=','p.id')
            ->join('pos_session AS ps0', 'ps0.pos_id', '=', 'ps1.pos_id')
            ->where('ps1.id','=',DB::raw('MAX(ps0.id)'))
            ->orWhere('p.site_id','=',2)
            ->orderBy('ps1.pos_id')
            ->get();

希望它能帮助:)

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