将图像从Android上传到MySQL数据库

问题描述 投票：0回答：2

PHP代码

这个PHP代码有什么问题吗？

 <?php
    require '../db_connect.php';
    if (isset($_POST['message']) && !empty($_POST['message']) or isset($_POST['img_file']) && !empty($_POST['img_file']) or isset($_POST['video_file']) && !empty($_POST['video_file']))
    {
        $message=$_POST['message'];
        $user_id=$_POST['user_id'];
        //$user_id=1;
        date_default_timezone_set('Asia/Kolkata');
        $date = date('Y-m-d H:i:s');

        $query=mysqli_query($con,"INSERT INTO posts(user_id,post_description,is_active,created_at) values('".$user_id."','".$message."',1,'".$date."')");

        if($query){
             $i_post_id = mysqli_insert_id($con);
             if(isset($_POST['img_file'])){
                 $sourcePath = $_POST['img_file'];
                 // create dir if not exists
                if(!is_dir('../img/Post')){
                     mkdir('../img/Post',0777,true);
                }
                $s_file_name = time()."_".$_POST['img_file'];
                $targetPath = "../img/Post/".$s_file_name;
                if(move_uploaded_file($sourcePath,$targetPath)) {
                    function compress($source, $destination, $quality) {
                        $info = getimagesize($source);
                        if ($info['mime'] == 'image/jpeg') 
                            $image = imagecreatefromjpeg($source);
                        elseif ($info['mime'] == 'image/gif') 
                            $image = imagecreatefromgif($source);
                        elseif ($info['mime'] == 'image/png') 
                            $image = imagecreatefrompng($source);

                        imagejpeg($image, $destination, $quality);
                        return $destination;
                    }
                    $source_img = $targetPath;

                    if(!is_dir('../img/Post/compress')){
                        mkdir('../img/Post/compress');
                    }
                    $destination_img = '../img/Post/compress/'.$s_file_name;

                    $d = compress($source_img, $destination_img, 50);

                    $i_file_type = 1; // 1 for image.
                    $query=mysqli_query($con,"INSERT INTO post_files(post_id,file_name,file_type,is_active) values('".$i_post_id."','".$s_file_name."',$i_file_type,1)");

                }
            }
            if(isset($_POST['video_file'])){
                    //echo "in";
                $sourcePath = $_POST['video_file'];
                 // create dir if not exists
                if(!is_dir('../img/Post')){
                     mkdir('../img/Post',0777,true);
                }

                $s_file_name = time()."_".pathinfo($_POST['video_file'], PATHINFO_FILENAME).".mp4";
                $s_file_name = str_replace(' ', '_', $s_file_name);
                $targetPath = "../img/Post/convert/".$s_file_name; 
                 if(!is_dir('../img/Post/convert')){
                     mkdir('../img/Post/convert',0777,true);
                 }
                $s_post_path = dirname(__FILE__).'/';

                 $handbrake = "HandBrake/HandBrakeCLI";
                 $cmd = $s_post_path.$handbrake." -i ".$sourcePath." -o ".$s_post_path.$targetPath." -e x264 -q 25 -r 15 -B 64 -X 480 -O";
                    passthru($cmd,$err);

                        $i_file_type = 2; // 2 for video.
                        $query=mysqli_query($con,"INSERT INTO post_files(post_id,file_name,file_type,is_active) values('".$i_post_id."','".$s_file_name."',$i_file_type,1)");
            }
            $response["success"] = 1;
            $response["message"] = "Post successfully added.";

            // echoing JSON response
            echo json_encode($response);
        }
        else{
            $response["success"] = 0;
            $response["message"] = "Oops! An error occurred.";

            // echoing JSON response
            echo json_encode($response);
        }
    }
    ?>

当我将图像上传到Mysql数据库时，它没有上传并将我的图像显示为LOG中的字符串，例如=

    img_file = /9j/
4 AAQSkZJRgABAQAAAQABAAD / 2 wBDABALDA4MChAODQ4SERATGCgaGBYWGDEjJR0oOjM9PDkz
ODdASFxOQERXRTc4UG1RV19iZ2hnPk1xeXBkeFxlZ2P / 2 wBDARESEhgVGC8aGi9jQjhCY2NjY2Nj
Y2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2NjY2P / wAARCBBACSQDASIA
AhEBAxEB / 8 QAGwABAQEBAQEBAQAAAAAAAAAAAQACBwYFBAP / xABKEAACAgIBAwMDAQUEBgkDAAsA
AREhMUECA1FhBAVxBhKBkQc1cqGxEyIyNBQVFjNCUiM2U1RVYnOSwRclgiTR4fBDRPFjRSaD / 8 QA
FgEBAQEAAAAAAAAAAAAAAAAAAAEC / 8 QAFxEBAQEBAAAAAAAAAAAAAAAAAAERQf / aAAwDAQACEQMR
AD8A8KSAQ2SJQwl4kKkIDoBRP + YJzsANESJ6AGwFuydBEoUypJFoAGPIOhTJhGS4uHOSFAUkxaoy
FQpUSyKj5AGoImKrIQNUCN8nWDAUr5KARqHEgDKARtpAZRpA4yimwEzAvlsJAYrJkQgK0UmbEI0n
CJw1INMgozZaGQCFDNGfgtWBCncfzDRQ9AacSD8otWEgX4FKVbKu5UBlijX2zaKKkDM + BmhwZeAA
skiQCObQRQzoCkHdiAEi2SkvufgCFcmgIBaWUBFYQ9yXYCASqSTL5CjANi2AQosgkIAQGkpCpRcg
LUEkArFghgoAk7RN33JgBrko2ZGXEGQJGo2AzLloAYCiYBJFBAOhULILGS1kCIcAgADTUujIChXk
BAmSZABrjyFxEyYNPAU / kzspKQifJom0ElMWBJjYNtsUBFBovIA + weB2DcvADgDWUDQAUeSspryB
CoMjkCblisGZIBFKwSbcI0lDsAecByiDTdhyYVg1RQgCEHkiCJCBICFFWNkAtwoyZZCAEUdyAmSR
CAFUGknEmQIVACgLkgNOzLCqSAUpQFAvjAvwWVYGSNYLAAREqAimx5OTIGn4Ak2hmwIGTGmooDIG
l5BqwIoEtAEUQsgicaJQTBIBQyZJhTJNgWwGSGIZOvkDI6AQGKMipIBwv6gKVTIOgIs6IpgCLkoy
VSTsICKCXYCGSQutWBlMQYAbbWjJEBQLkgACIUgJG0jIgDBpp2jSyDlu2BEOF8hoAFXsikBVASNO
I / AOMwOME6GG6SCsyT5N5JloAkiICEkotloDStBkuJAGyVDBPEAQFaKAIiggLQ6gLyKfcCZmLNNz
oGghVZQNogAhkCA0n3Ll3MspYCvktkKCp9gTs0ZAiIFkBstEMaoDItt3BNFbAkL5S8AIFIMtyacN
YAOKHnGpBNwMwFFg0bT8GXC0EGkggZ0UqZAoayREAoi0KAKFudQH9SbQEThLyTa0ZAUOUCJAaqCg
AYE / CK0EspkBvZDqAYCrJ5DBrYBDMs0wdAREh5SqgDIkDAhQCArIEKAJKSYAMIoJEnAAyEoABKoI
CBi8wQAaTiPAIVkCJqi2TwBkjULsQAsSTlgaUACoU5yUFIVMJIgJFEMhXKoCLi7Lk5eSifgnmsBU
sgOBQRkDSiHP4Cu4FaJW4FpQSnIA1BI1oHgB5TCsybMvuAERAQrALIgJl5FpwULYAy8DU5FhQkmK
LJLABlwDNQobMgAoi / AQwAlhhU4wRBhgbcQg1kyapbCMkMEuKeaAqSAXQSFQqUArIE / INWOgkIQG
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如何从这个php文件上传图片？这个php文件有什么问题？

php android json
2个回答
1
投票

我建议在发送之前将图像转换为Base64字符串，然后使用PHP代码将其转换回后端的图像。您可以使用以下代码将图像转换为Base64：

public void toStringImage(Bitmap bmp) {
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        bmp.compress(Bitmap.CompressFormat.JPEG, 100, baos);
        byte[] imageBytes = baos.toByteArray();
        String encodedImage = Base64.encodeToString(imageBytes, Base64.DEFAULT);
}

使用您的首选库将encodedImage字符串发送到您的PHP Web服务（我通常使用Volley）。

收到encodedImage后，使用以下代码将其转换回图像并将其存储在数据库的任何位置：

$imageString = $_POST['encodedImage'];
$path = "../$name.jpg";
file_put_contents($path, base64_decode($imageString));

存储后，在MySQL数据库中插入图像的位置，以便您可以使用它来检索图像。

编辑：

不要使图像上传如此复杂，请尝试以下PHP代码：

if(isset($_POST['img_file'])){
    $sourcePath = $_POST['img_file'];
    // create dir if not exists
    if(!is_dir('../img/Post')){
         mkdir('../img/Post',0777,true);
    }
    $date = date_create();
    $s_file_name = $user_id.date_format($date, 'U');
    $targetPath = "../img/Post/$name.jpg";
    file_put_contents($targetPath, base64_decode($sourcePath));
    $i_file_type = 1; // 1 for image.
    $query=mysqli_query($con,"INSERT INTO post_files(post_id,file_name,file_type,is_active) values('".$i_post_id."','".$s_file_name."',$i_file_type,1)");
}

在我的GitHub repo：ImagetoString上检查相同的代码

0
投票

在你的PHP文件中试试这个，它对我有用：

$host = "localhost";
$user = "root";
$password = "";
$dbname = "image_db";

$db = mysqli_connect($host, $user, $password, $dbname);

if ($db) {
  echo "connected";
}
else{
  echo "not connected";
}

    $image = $_FILES['image']['name'];
    $image_text = mysqli_real_escape_string($db, $_POST['img_name']);

    $target = "images/".basename($image);

    $sql = "INSERT INTO images_tbl (image, img_name) VALUES ('$image', '$image_text')";
    mysqli_query($db, $sql);

    if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
        $msg = "Image uploaded successfully";
      echo $msg;
    }else{
        $msg = "Failed to upload image";
      echo $msg;
    }

  $result = mysqli_query($db, "SELECT * FROM images_tbl");
?>
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