CS50马里奥金字塔颠倒不明白为什么

Question

在在这里问这个问题之前我想了很久，但我现在花了太多时间试图在不作弊的情况下解决这个问题。 CS50 mario ps1（不太舒服）要求*简单的左对齐（首先）金字塔，但我的代码给了我它颠倒，我不明白为什么。

#include <cs50.h>
#include <stdio.h>

int main (void)
{
    int n;
    do
    {
        n = get_int("Pyramid Height: ");
    }
    while (n < 1 || n > 8);
    for (int i = 0; i < n; i++) 
    {
        for (int j = 0; j < n - i ; j++)
            printf("#");
        for (int j = 0; j < n - i; j++) 
        {
            printf(" ");
        }
        printf("\n");
    }
}

如果此类问题经常出现，我很抱歉，但我确实需要您的帮助。 预先感谢。

编辑：

• 预期结果：

........#
.......##
......###
.....####
....#####
...######
..#######
.########

• 我可以稍后将点更改为空格，这只是为了可视化；

• 高度限制是8，所以我猜每行总是八个字符；

• 我实际上添加了尾随空格，以便金字塔可以右对齐，我之前提到过错误；

• 我要查看如何调试小程序？;

• 抱歉，我是新手，我不知道这里和堆栈交换之间有区别，会研究一下。

*抱歉“meh”英语，这不是我的母语。

Answer 1

看看我的代码和你的代码有什么区别（尤其是如何计数）：

void draw(int n, int align, int dir)
{
    for (int i = 1; i <= n; i++) 
    {
        if(align)
        {
            for(int s = 0; s < (dir ? (n - i) : i - 1); s++)
            {
            printf(" ");
            }
        }
        for (int j = 0; j < (dir ? i  : (n - i + 1)) ; j++)
        {
            printf("#");
        }
        printf("\n");
    }
}

int main (void)
{
    draw(8,1,0);
    printf("\n");
    draw(8,1,1);
    printf("\n");
    draw(8,0,0);
    printf("\n");
    draw(8,0,1);
}

https://godbolt.org/z/7YT16j

Answer 2

我的代码给了我它颠倒，我不明白为什么

让我们看看代码是什么样的

// There's a loop executed n times. The body prints a line, so n lines are printed.
// In case you have doubts, the characters are normally printed top to bottom and
// left to right.
for (int i = 0; i < n; i++) 
{
    // The following loop prints (n - i) characters '#' at the beginning
    // of each line. That's NOT what you are supposed to do, kind the opposite.
    for (int j = 0; j < n - i ; j++)
        printf("#");
    // You should first print the spaces, then the '#'s, starting from 1 '#' at
    // the first line and increasing the number by one at each line (so you have
    // to change the condition in the loop accordingly).

    // This loop prints the right amount of spaces, but only after
    // all the '#'s and just before the end of the line, so that you just
    // can't see them (change the printed char to '.' to visualize those).
    for (int j = 0; j < n - i; j++) 
    {
        printf(" ");
    }

    // Note that you could use putchar('\n'), here and previously, to print
    // only one char, instead of using printf() to print string literals. 
    printf("\n");
}

Answer 3

这里是CS50这个问题的高级版本。它包含您问题的答案，也是解决方案的一部分。我强烈建议你看一下这个，不要复制粘贴它，而是尝试自己写下来。

#include <cs50.h>
#include <stdio.h>

int main(void){
    int pyramidHeight;
    do {
    pyramidHeight = get_int("Please provide puramid height..: ");
    }
    while (pyramidHeight < 1 || pyramidHeight > 8);

    // looping over the left side of the pyramid
    for (int i = 0; i < pyramidHeight; i++){
        int count = i+1;
        int spaces = pyramidHeight-(i+1);
        //first empty spaces to the left
        for(int h = 0; h < spaces; h++){
            printf(" ");
        }
        //then hashes
        for (int j = 0; j < count; j++){
            printf("#");
        }
        //space between pyramid hashes
        printf(" ");
        // hashes to the right of hte pyramid
        for (int k = 0; k < count; k++){
            printf("#");
        }
        // spaces to the right of the pyramid
        for(int f = 0; f < spaces; f++){
            printf(" ");
        }
        printf("\n");
    }
}