像 Python 请求一样在 javascript 中请求

Question

我之前有 python selenium 代码，现在正在迁移到 javascript puppeteer rigth，但是在为任何页面上传我的屏幕截图元素时遇到一些问题。这是我上传图片的 python 代码

file = {'fileToUpload': open('./up/' + emiten + '.png', 'rb')}
    resp = requests.post('/upload.php',
                           files=file)
    print(resp.text)

我使用 .php 文件直接接收任何图像

<?php
$target_dir = "upload/";
$watermarkImagePath = 'wm.png';
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is an image - " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        echo "File is not an image.";
        $uploadOk = 0;
    }
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
    echo "Kepentok kah? ";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Maaf gabisa usil.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)){
      $watermarkImg = imagecreatefrompng($watermarkImagePath);
      $im = imagecreatefrompng($target_file);

      $marge_right = 17;
                 
      $sx = imagesx($watermarkImg);

      imagecopy($im, $watermarkImg, imagesx($im) - $sx - $marge_right, 0, 0, 0, imagesx($watermarkImg), imagesy($watermarkImg));
                 
      imagepng($im, $target_file);
      imagedestroy($im);
      
        echo "Upload file ". basename( $_FILES["fileToUpload"]["name"]). " telah berhasil.";
    } else {
        echo "Maaf gabisa usil.";
    }
}
?>

javascript 中有相同的方法吗？已经将 axios 与 formData 和 nodefetch 一起使用，但没有任何效果 我希望在不更改 .php 文件的情况下在 javascript 中有简单的代码