如何处理使用带有状态的密封类的 ViewModel 内部的程序错误？

Question

尽力去理解

StateFlow

和

States

。根据android文档，我们有这段代码：

    class LatestNewsViewModel(
    private val newsRepository: NewsRepository
) : ViewModel() {

    // Backing property to avoid state updates from other classes
    private val _uiState = MutableStateFlow(LatestNewsUiState.Success(emptyList()))
    // The UI collects from this StateFlow to get its state updates
    val uiState: StateFlow<LatestNewsUiState> = _uiState

    init {
        viewModelScope.launch {
            newsRepository.favoriteLatestNews
                // Update View with the latest favorite news
                // Writes to the value property of MutableStateFlow,
                // adding a new element to the flow and updating all
                // of its collectors
                .collect { favoriteNews ->
                    _uiState.value = LatestNewsUiState.Success(favoriteNews)
                }
        }
    }
}

// Represents different states for the LatestNews screen
sealed class LatestNewsUiState {
    data class Success(val news: List<ArticleHeadline>): LatestNewsUiState()
    data class Error(val exception: Throwable): LatestNewsUiState()
}

现在，如果我想处理错误，根据

LatestNewUiState

密封类 - 我是否必须创建另一个支持属性，如

_uiStateError = ...

有一个地方，放入错误，然后创建另一个 val ,

val uiStateError: MutableStateFlow<LatestNewsUiState> = _uiStateError

然后，用

viewModelScope.launch

包裹

try/catch

，每当发生错误时，只需将

Throwable

推到

_uiStateError

？或者有什么更好的方法吗？