pygame键盘未正确注册

问题描述 投票:0回答:1

我制作了一个游戏,该游戏只能检测2个玩家的动作,但是有时候,一次按下多个键然后松开时,并不能检测到所有键都被松开了(其中一个键仍在我尝试在程序中多次调用“ keyup”功能,但似乎无济于事。只有一名玩家会发生这种情况,但由于一次按下的键较少,这种情况很少发生。这是代码:

import pygame,sys

pygame.init()

DPROZOR=(1200,800)
DIGRAC=(100,100)
KORAK=0.5

ziv=True
x1,y1=(float(DPROZOR[0]/2-DIGRAC[0]/2),float(DPROZOR[1]-DIGRAC[1]))
x2,y2=(float(DPROZOR[0]/2-DIGRAC[0]/2),0)
pozicija1=[x1,y1]
pozicija2=[x2,y2]
desno1,levo1,gore1,dole1=(False,False,False,False)
desno2,levo2,gore2,dole2=(False,False,False,False)

prozor=pygame.display.set_mode(DPROZOR)

def crtaj():
    prozor.fill(pygame.Color("skyblue"))
    pygame.draw.rect(prozor,pygame.Color("gold"),(pozicija1,DIGRAC))
    pygame.draw.rect(prozor, pygame.Color("red"), (pozicija2, DIGRAC))

def keyDown1():
    global desno1,levo1,gore1,dole1

    if(event.type == pygame.KEYDOWN):
        if(event.key == pygame.K_RIGHT): desno1=True
        if(event.key == pygame.K_LEFT): levo1=True
        if(event.key == pygame.K_UP): gore1=True
        if(event.key == pygame.K_DOWN): dole1=True

def keyDown2():
    global desno2,levo2,gore2,dole2

    if(event.type == pygame.KEYDOWN):
        if(event.key == pygame.K_d): desno2=True
        if(event.key == pygame.K_a): levo2=True
        if(event.key == pygame.K_w): gore2=True
        if(event.key == pygame.K_s): dole2=True

def keyUp1():
    global desno1,levo1,gore1,dole1

    if(event.type == pygame.KEYUP):
        if(event.key == pygame.K_RIGHT): desno1=False
        if(event.key == pygame.K_LEFT): levo1=False
        if(event.key == pygame.K_UP): gore1=False
        if(event.key == pygame.K_DOWN): dole1=False

def keyUp2():
    global desno2,levo2,gore2,dole2

    if(event.type == pygame.KEYUP):
        if(event.key == pygame.K_d): desno2=False
        if(event.key == pygame.K_a): levo2=False
        if(event.key == pygame.K_w): gore2=False
        if(event.key == pygame.K_s): dole2=False

def kretanje1():
    global x1,y1,pozicija1

    if(desno1): x1+=KORAK
    if(levo1): x1-=KORAK
    if(x1 < 0): x1+=KORAK
    if(x1 > DPROZOR[0] - DIGRAC[0]): x1-=KORAK

    if(gore1): y1-=KORAK
    if(dole1): y1+=KORAK
    if(y1 < 0): y1+=KORAK
    if(y1 > DPROZOR[1] - DIGRAC[1]): y1-=KORAK

    pozicija1=[x1,y1]

def kretanje2():
    global x2,y2,pozicija2

    if(desno2): x2+=KORAK
    if(levo2): x2-=KORAK
    if(x2 < 0): x2+=KORAK
    if(x2 > DPROZOR[0] - DIGRAC[0]): x2-=KORAK

    if(gore2): y2-=KORAK
    if(dole2): y2+=KORAK
    if(y2 < 0): y2+=KORAK
    if(y2 > DPROZOR[1] - DIGRAC[1]): y2-=KORAK

    pozicija2=[x2,y2]

while ziv:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()

    crtaj()

    keyDown1()
    kretanje1()
    keyUp1()
    kretanje1()

    keyDown2()
    kretanje2()
    keyUp2()
    kretanje2()

    print()
    print(desno1,levo1,gore1,dole1)
    print()
    print(desno2,levo2,gore2,dole2)
    print()

    pygame.display.update()

左=左

desno = right

gore = up

dole =向下

ziv = alive

DPROZOR =窗口尺寸

DIGRAC =玩家人数

KORAK = step

pozicija = pozition

kretanje =运动

crtaj = draw

python pygame keypress keyup
1个回答
1
投票

这是Indentation的问题。您必须在事件循环而不是应用程序循环中评估事件:

while ziv:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()

        keyDown1()
        kretanje1()
        keyUp1()
        kretanje1()

        keyDown2()
        kretanje2()
        keyUp2()
        kretanje2() 

    crtaj()

    # [...]
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