如何在python中找到LineString最接近坐标的点

Question

我有以下代码...

import osmnx as ox
latitude = 51.217220
longitude = 4.418535

p = ox.Point(latitude, longitude)
line = ox.LineString([(4.4203843 , 51.2154117), (4.420431, 51.2159018), (4.4204697, 51.2163913), (4.4204833, 51.2166588),  (4.4204243, 51.2168076), (4.4203641, 51.2169564), (4.4203409, 51.2170063), (4.4202929 ,51.2171074), (4.4202355 ,51.2171806), (4.420205, 51.2172067), (4.4201654, 51.2172246), (4.4201077 ,51.2172411), (4.4200562 ,51.2172511), (4.4194807 ,51.217338), (4.4190475 ,51.2174025), (4.4179023 ,51.2175729), (4.4178548 ,51.21758), (4.4177154 ,51.2176008)])
np = nearest_points(line, p)[0]
print(np)

但是输出变为

要点（4.4203843 51.2154117）

而且从这LineString到我的观点，这显然不是最接近的点。我在做什么错？

Answer 1

nearest_points是什么？您的代码段不可重现，但这是一个很好的猜测：LineString中的坐标表示为（经度，纬度），而Point表示为（纬度，经度）。