Mailchimp API帖子成员批处理操作

Question

[我发现当我向Mailchimp API提交批处理操作以将成员添加到Mailchimp听众时，操作失败，并显示此错误...

[{\"field\":\"email_address\",\"message\":\"This value should not be blank.\"}]

这很奇怪，因为我的批处理操作指定了电子邮件地址。

        ArrayList<MailchimpOperation> operations = new ArrayList<MailchimpOperation>();
    for (Contact contact : contacts) {
        MailchimpOperation operation = new MailchimpOperation();
        operation.method = "POST";
        operation.path = "lists/" + audienceid + "/members";
        NewMember newMember = new NewMember();
        newMember.email_address = contact.email;
        MergeFields mf = new MergeFields();
        mf.FNAME = contact.firstname;
        mf.LNAME = contact.lastname;
        newMember.merge_fields = mf;
        newMember.status = "subscribed";
        operation.body = newMember.toString();
        operation.operation_id = "add_batch_" + batchNumber + "_to_mailchimp_audience_" + audienceid;
        operations.add(operation);
    }

[我在一些堆栈溢出文章中看到该operation.body应该是一个JSON对象。我也尝试过...

ArrayList<MailchimpOperation> operations = new ArrayList<MailchimpOperation>();
    for (Contact contact : contacts) {
        MailchimpOperation operation = new MailchimpOperation();
        operation.method = "POST";
        operation.path = "lists/" + audienceid + "/members";
        NewMember newMember = new NewMember();
        newMember.email_address = contact.email;
        MergeFields mf = new MergeFields();
        mf.FNAME = contact.firstname;
        mf.LNAME = contact.lastname;
        newMember.merge_fields = mf;
        newMember.status = "subscribed";
        operation.body = newMember;
        operation.operation_id = "add_batch_" + batchNumber + "_to_mailchimp_audience_" + audienceid;
        operations.add(operation);
    }

这会产生错误...

Mailchimp error: The resource submitted could not be validated. For field-specific details, see the 'errors' array.,mailchimp error 1 Schema describes string, object found instead,mailchimp error 2 Schema describes string, object found instead

并且如果我像这样显式设置operation.body，则操作成功...

operation.body = "{\"merge_fields\":{\"FNAME\":\"" + contact.firstname + "\",\"LNAME\":\""
                + contact.lastname + "\"}, \"email_address\":\"" + contact.email + "\", \"status\":\"subscribed\"}";

所以为什么我在第一个设置operation.body = newMember.toString()的方法失败了？

Answer 1

解决方案是不使用.toString（），而是使用此...

    operation.body = new ObjectMapper().writeValueAsString(newMember);