macOS软件包之间的双向数据交换（交换）

Question

如何在macOS捆绑软件之间传递数据？

例如：MyApp.app将数据发送到MyBundle.bundle中的函数或类初始化程序，该函数或类初始化程序对其执行自己的逻辑。它甚至可以返回一个值，然后MyApp.app可以对其进行进一步处理。

示例，一个Objective-C函数：

    void initialise(unsigned int frameCount) {…} // not a class initialiser btw

我尝试过：

• 在MyBundle中声明一个类，然后使用Foundation.Bundle将其加载到MyApp中：

  let class = (Bundle(url: url)!.classNamed("MyClass")! as! NSObject.Type).init()
  // class is an instance of NSObject, but I can override the `init()` method 
  // (in MyBundle) to do whatever. I have not found a way to implement an 
  // initialiser with parameters, and it still be recognised here.
  

• 在MyBundle中声明一个函数，然后使用CFBundleGetFunctionPointerForName进行检索。

  var bundles = CFBundleCreateBundlesFromDirectory(kCFAllocatorDefault, bundleDirectory, bundleExtension)! as Array
  var bundle1 = bundles.first! as! CFBundle
  
  var untypedFunctionPointer = CFBundleGetFunctionPointerForName(bundle, "initialise" as CFString)!
  
  let imp = unsafeBitCast(untypedFunctionPointer, to: IMP.self)
  
  let function = unsafeBitCast(imp, to: (@convention(c)(CUnsignedInt) -> Void).self)
  // If I specify parameters here, pass them in below, then try to use them in my objective c function, I get exc_bad_access.
  
  function(CUnsignedInt(1.0)) // Will work only when not trying to access parameters in the original objective c function.
  
  
  
  // Whatever @convention(c) function signature I use, the parameters are unusable in Objective C.
  

两者的关键问题是我无法将数据作为参数传递。因此，打印语句将起作用，但不能使用参数。

Answer 1

基于您的问题Call Swift function from Bundle和https://stackoverflow.com/a/56281093/5329717中的注释，我想您是在Swift中通过UnsafeBufferPointer参数动态调用函数指针或Objective-C方法之后。