[我正在尝试保存应用程序中的Django模型后打印一些文本。
我已经在同一应用程序的signals.py文件中为此创建了一个信号。
但是,它不能按预期方式工作(即,未调用函数且未打印文本)
但是如果我将接收器函数放在我创建的模型下面的models.py文件中,它就可以正常工作(即,正在调用该函数并且已打印文本)
我已经仔细阅读了文档,以检查是否有必要将信号放置在特定的文件或位置。似乎没有任何此类限制。
https://docs.djangoproject.com/en/3.0/topics/signals/#django.dispatch.receiver
如果没有这样的限制,为什么行为方式不同?
signals.py:
from django.db.models.signals import post_save
from django.dispatch import receiver
from aws_envs.models import UserStack
@receiver(post_save, sender=UserStack)
def create_user_stack(sender, **kwargs):
print("creating user stack now")
models.py:
class UserStack(BaseModel):
name = models.CharField(max_length=50)
email = models.EmailField(unique=True, max_length=50, blank=False)
enabled = models.BooleanField(default=True)
def save(self, *args, **kwargs):
print(f"Creating stack with data: {self.name, self.email}")
super(UserStack, self).save(*args, **kwargs)
def __str__(self):
return self.name, self.email
''post.apps.PostConfig'
from django.apps import AppConfig
class postConfig(AppConfig):
name = 'post'
def ready(self):
# signals are imported, so that they are defined and can be used
import post.signals
# post/signals.py
from django.dispatch import receiver
from django.db.models.signals import post_save
from post.models import Post
def send():
print("send email!")
@receiver(post_save, sender=Post, dispatch_uid='Post_post_save')
def send_email(instance, **kwargs):
send()