多项式从 file.txt 加载到终端时出现问题

Question

您好，我的功能有问题。基本上我需要将多项式从 file.txt 加载到终端。 基本上，我每行都有几个系数，1 个多项式等于 1 行。当我在终端上尝试输出时很奇怪。 1 系数不打印，3 行/3 多项式也不打印。

这是我的功能：

polynom* vytvorZeSouboru(const char *soubor, int *pocet) {
    FILE *file = fopen(soubor, "r");

    if (file == NULL) {
        perror("Chyba pri otevirani souboru");
        exit(EXIT_FAILURE);
    }

    // Number of polynomials in the file - set to 0 at the beginning
    *pocet = 0;

    // Find out how many rows (polynomials) are in the file
    int c;
    while ((c = fgetc(file)) != EOF) {
        if (c == '\n') {
            (*pocet)++;
        }
    }

    // Let's go back to the beginning of the file
    rewind(file);

    // Pole polynomů
    Polynom *polePolynomu = (Polynom*)malloc(*pocet * sizeof(Polynom));

    //  Reading polynomials from a file
    for (int i = 0; i < *pocet; ++i) {
        int pocetKoeficientu;
        if (fscanf(file, "%d", &pocetKoeficientu) != 1) {
            fprintf(stderr, "Chyba pri cteni poctu koeficientu polynomu ze souboru.\n");
            exit(EXIT_FAILURE);
        }
       

        // Polynomial initialization
        polePolynomu[i].koeficienty = (int*)malloc(pocetKoeficientu * sizeof(int));
        polePolynomu[i].pocetKoeficientu = pocetKoeficientu;

        // Načtení koeficientů polynomu
        for (int j = 0; j < pocetKoeficientu; ++j) {
            if (fscanf(file, "%d", &polePolynomu[i].koeficienty[j]) != 1) {
                fprintf(stderr, "Chyba pri cteni koeficientu polynomu ze souboru.\n");
                exit(EXIT_FAILURE);
            }
        }
    }

    // Zavření souboru
    fclose(file);

    return polePolynomu;
} ```


void vypisPolynomy(const Polynom *polePolynomu, int pocet) {
    for (int i = 0; i < pocet; ++i) {
        printf("Polynom %d: ", i + 1);
        for (int j = 0; j < polePolynomu[i].pocetKoeficientu; ++j) {
            printf("%d ", polePolynomu[i].koeficienty[j]);
        }
        printf("\n");
    }
}


int main() {
    int pocet, i;
    
      const char *cestaKSouboru = "vytvorZeSouboru.txt"; 
     
    Polynom *polePolynomu = vytvorZeSouboru(cestaKSouboru, &pocet);
    
      vypisPolynomy(polePolynomu, pocet);


    // Memory release
     for (int i = 0; i < pocet; ++i) {
        free(polePolynomu[i].koeficienty);
      }
    free(polePolynomu);

     

Answer 1

//  Reading polynomials from a file
for (int i = 0; i < *pocet; ++i) {
    int pocetKoeficientu;

... } // 进一步使用“pocetKoeficientu”

稍后使用变量“int pocetKoeficientu;”超出范围（仅在 for 循环内有效）。将其放在 for 循环的开头： // 从文件中读取多项式 int pocetKoeficcientu； 对于 (int i = 0; i < *pocet; ++i) { ... } // further use of "pocetKoeficientu"