"orgId": 1,
"orgName":"orgOne"
"empList": [
{
"empId": 1,
"empName":"emp1"
},
{
"empId": 2,
"empName":"emp2"
},
{
"empId": 3,
"empName":"emp3"
}
]
},
{
"orgId": 2,
"orgName":"orgTwo"
"empList": [
{
"empId": 2,
"empName":"emp2"
},{
"empId": 3,
"empName":"emp3"
}
]
}
下面的查询给出empId = 2的orgId
SELECT d.orgId
FROM default AS d
WHERE ANY e IN d.empList SATISFIES e.empId = 2 END;
如果您看起来与众不同,可以解释更多细节。